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yanalaym [24]
2 years ago
13

Root 15 * root 10 It is urgent

Mathematics
1 answer:
nydimaria [60]2 years ago
6 0

6 \sqrt{5}

Step-by-step explanation:

\sqrt{15}  \times  \sqrt{10}

=  \sqrt{3 \times 5}  \times  \sqrt{2 \times 5}

= 3 \sqrt{5}  \times 2 \sqrt{5}

= 6 \sqrt{5}

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Can someone help me with this problem
chubhunter [2.5K]

n = 13\frac{1}{3}

This is found by dividing 32 by 2.4

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3 years ago
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A tunnel is 30 yards long and 15 yards wide. The height of the tunnel walls is 5 yards before the curve of the cylinder-shaped c
Karolina [17]
The tunnel is made of two shapes and we can find the volume of each.
Cuboid volume=15×5×30=2250 cu yds.
Half cylinder volume=π(7.5)²30/2=843.75π=2649.38 cu yds.
Total volume=4899.38 cu yds.
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3 years ago
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Divide 120 in the ratio of 1:2
antiseptic1488 [7]

Ratio given 1:2

Let's suppose the ratio as x : 2x

Adding the ratio = 3x

\frac{x}{3x}  \times 120 \\ =40

\frac{2x}{3x}  \times 120 \\= 80

40 and 80 are in the ratio 1:2 of 120.

Hope it helps!!!

7 0
3 years ago
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One pipe can empty a tank 5 times faster than another pipe can fill the tank. Starting with a full tank, if both pipes are turne
xxTIMURxx [149]

Answer:

40 hours

Step-by-step explanation:

Let's say that the slower pipe can fill x amount of the tank in one hour. It adds x amount to the tank every hour. Therefore, we can say, for the slower pipe,

1 hour = x amount

Then, the faster pipe empties the tank 5 times faster than the slower pipe fills it, so it removes 5 times the amount that the smaller pipe puts in, so for the faster pipe,

1 hour = -5x amount (negative to symbolize removing).

For the problem at hand, the tank starts at full, or 100%=1. It ends empty, or at 0% = 0. After 10 hours, if we only account for the slower pipe, we add x amount to the tank every hour, so we add 10 times that total, resulting in

1 + 10 * x as the ending result if we don't include the faster pipe. Then, the faster pipe removes 5x every hour, so in 10 hours, it removes 50x, so we have

1+10 * x - 50 * x as the final amount of stuff in the tank, which is equal to 0. Therefore, we have

1 + 10 * x - 50 * x = 0

1 - 40 * x = 0

add 40*x to both sides to isolate the x and its coefficient

1 = 40 * x

divide both sides by 40 to isolate x

x= 0.025

Therefore, the slower pipe adds 0.025, or 1/40 = 2.5% to the tank every hour. We want to figure out how long it would take for the slower pipe to fill up an empty tank, or turn it from 0% to 100% full.

Because the slower pipe adds 2.5% of the tank every hour, we can say that over y hours, it fills up

2.5% * y amount of the tank. We want to figure out how many hours it would take to make it 100% (we need to add 100% of the tank in the problem), so we can say

2.5% * y = 100%

divide both sides by 2.5% to isolate y

100%/2.5% = y = 40

5 0
3 years ago
Who knows the Babylonian method, and can help me!<br> **see picture below**
PSYCHO15rus [73]
This is an iteration method for finding the square root.

The ? is also your first initial guess.

? = 10.5

The iteration formula for the square root is actually.

√n =      (x + n/x)÷2.

Where x is your guess.
3 0
3 years ago
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