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DENIUS [597]
3 years ago
11

What can you triple and then subtract by 7 to get -1

Mathematics
1 answer:
iVinArrow [24]3 years ago
7 0

Answer:

2

Step-by-step explanation:

<em>let </em><em>the </em><em>number </em><em>be </em><em>x</em>

<em>The</em><em>n</em><em> </em><em>you </em><em>triple </em><em>the </em><em>x </em><em>and </em><em>minus </em><em>7 </em><em> </em><em>from </em><em>it </em><em>and </em><em>you </em><em>equate </em><em>it </em><em>to </em><em>-</em><em>1</em>

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Step-by-step explanation:

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3 years ago
Round 23 to the nearest ten
svetlana [45]

Answer:

20

23 is between 20 and 30, but it's closer to 20. So 23 is rounded down to 20.

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The table shows the number of students in a class who play on a school team and/or are members of a school club:
eimsori [14]
This one is very simple.

create a simple equation to find out

15 = 12 + x

subtract 12 from each side

x= 3

the missing number is 3

or, to be even simpler, take the total, subtract the total from the number you know and the difference is the missing number.

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3 years ago
Find the value of m .​
kondor19780726 [428]

Step-by-step explanation:

if the 2 matrices are inverse, then their product must be the identity matrix

1 0

0 1

so,

m×3 + 2×-7 = 1

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7 0
2 years ago
Discrete Mathematics I
faust18 [17]

ANSWER



The general solution is 86+280n, where n is an  integer



<u>EXPLANATION</u>



In order  to solve the linear congruence;



33x \equiv 38(mod\:280)



We need to determine the inverse of 33 (which is a Bézout coefficient for 33).



To do that we must first use  the Euclidean Algorithm to verify the existence of the inverse by showing that;



gcd(33,\:280)=1



Now, here we go;



280=8\times33+16



33=2\times 16+1



16=2\times 8+0



The greatest common divisor is the last remainder before the remainder of zero.



Hence, the gcd(33,\:280)=1.



We now express this gcd of 1 as a linear combination of  33 and 280.



We can achieve this by making all the non zero remainders the subject and making a backward substitution.



1=33-2\times 16--(1)



16=280-33\times8--(2)



Equation (2) in equation (1) gives,



1=33-2\times (280-8\times33)



1=33-2\times 280+16\times33



1=17\times33-2\times 280



The above linear combination tells us that  17 is the inverse of 33.



Now we multiply both sides of our congruence relation by 17.



17\times 33x \equiv 17\times 38(mod\:280)



This implies that;



x \equiv 646(mod\:280)



x \equiv 86.



Since this is modulo, the solution is not unique because any integral addition or subtraction of the modulo (280 in this case) produces an equivalent solution.



Therefore the general solution is,



86+280n, where n is an  integer

6 0
3 years ago
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