The number of different groups can be found by finding 9C3 (Using combinations)
We will find combinations from n = 9 to r = 3
Therefore, 9C3 = 9!/6!*3! = (9*8*7*6!)/(6!*3*2)
= 3*4*7
= 84 ways.
Answer
I think it is number 5
Step-by-step explanation:
Answer:
Step-by-step explanation:
57.6
I would convert them to improper fractions and then multiply. The improper fractions would be 35/4*13/6, and then you multiply across, 455/24, and that doesn't reduce, but you can convert it back to a mixed number, which is 18 23/24.