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3 years ago

15

jenny had some candy to give to her three children she first took nine pieces for herself and then evenly divided the rest among

her children each child received three pieces with how many pieces did she start

1 answer:

Gwar [14]3 years ago

4 0

Answer:

18 pieces of candy

Step-by-step explanation:

9+3+3+3=18

Hope this helps!

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jolli1 [7]

5+23= 28 .........................

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3 years ago

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What is the probability of selection for any man in a proportionate random sample, where a sample of 100 will be drawn from a po

kolbaska11 [484]

Working Principle: Stratified Random Sampling

nx = (Nx/N)*n

where:
nx = sample size for stratum x
Nx = population size for stratum x
N = total population size
n = total sample size

Given:

Nx = 100
N = 1000
n = 0.5*(1000) = 500

Required: Probability of Man to be selected

Solution:

nx = (Nx/N)*n
nx = (100/1000)*500 = 50 men

ny = (Nx/N)*n
ny = (100/1000)*500 = 50 women

Probability of Man to be selected = nx/(nx + ny)*100 = 50/(50+50)*100 = 50%

<em>ANSWER: 50%</em>

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3 years ago

Solve the following expression when<br> m = 5 and d = 4<br> m2 + 2d + 8 + d

Tatiana [17]

If you use substitution the should be answer 30

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3 years ago

Please help. I want to finish this problem so I can have fun. It is really hard for me. Plz.

mestny [16]

Answer:

x can be divided by 2,3,4,5,6

2 can be divided by 4, so is 3 to 6

so simply x can be divided by 4,5,6

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Step-by-step explanation:

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2 years ago

Solve the quadratic equation by completing the square.<br> x²–2x-12=0

inn [45]

Answer:

$(x-1)^2-13=0$

$x = \sqrt{13}+1$

Step-by-step explanation:

Completing the square is a method of rewriting a quadratic equation in the standard form such that it is in vertex form. The first step is to group the linear and quadratic terms, then factor out the coefficient of the quadratic term. After doing so, complete the square, add a value such that the linear and quadratic terms form a perfect square trinomial. Do not forget to balance the equation. The final step is to simplify.

$x^2-2x-12=0$

Group,

$(x^2-2x)-12=0$

Complete the square,

$(x^2-2x+1)-12-1=0$

Simplify,

$(x-1)^2-13=0$

Now solve the equation using inverse operations,

$(x-1)^2-13=0\\\\(x-1)^2=13\\\\x-1=\sqrt{13}\\\\x = \sqrt{13}+1$

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3 years ago