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Tom [10]
1 year ago
14

3m 2. What is the volume of this object? 1m 2 m 6 m 4 m 3 m

Mathematics
2 answers:
larisa86 [58]1 year ago
5 0

Answer:

60m^3

Step-by-step explanation:

The formula for volume of a rectangular prism is height*width*depth

We can see two distinct shapes here

First, we find the volume for the bigger shape

We can see the measurements that pertain to it...

Width is 6m, depth is 3m, and height is also 3m

Multiply those three, you get 54m^3

Now the smaller shape...

1m in width, 2m in height, and 3m in depth

Multiply those, get 6m^3

Add the two shapes together, 54+6=60m^3

vampirchik [111]1 year ago
4 0

Answer:

60m3

Step-by-step explanation:

my son got the right anser

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Three of the expressions will give the amount that remains after t years of a certain radioactive substance. Which expression is
MakcuM [25]

Answer:

The answer is D

Step-by-step explanation:

4 0
3 years ago
Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi
Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

The formula to compute covariance is:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

The formula to compute the variances are:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}

Consider the table attached below.

Compute the covariance as follows:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

                 =(5\times 165)-(30\times 25)\\=75

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50

Compute the correlation coefficient as follows:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

            =\frac{75}{\sqrt{230\times 50}}

            =0.69937\\\approx0.70

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0
3 years ago
2÷9<br><img src="https://tex.z-dn.net/?f=78%20%5Csqrt%7B%7D%20" id="TexFormula1" title="78 \sqrt{} " alt="78 \sqrt{} " align="ab
dimulka [17.4K]

Answer:

2 ÷ 9 ≈ 0.222

√78 ≈ 8.832

3 0
3 years ago
5-star rating and brainiest
Lelu [443]

Answer:

Step-by-step explanation:

What to do??

8 0
3 years ago
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Write a function rule for your bacterium in the table where h is the number of hours, and b(h) is the bacterium at h hours.
kolbaska11 [484]

Answer:

B(h)=x (subscript)-1*4+1 basically x from the previous generation times 4 plus one.

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5 0
3 years ago
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