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mixer [17]
4 years ago
11

What is -282 -20,320 written out

Mathematics
2 answers:
SVETLANKA909090 [29]4 years ago
8 0

-282 - 20,320

You change the minus to a plus and once you do that change the positive 20, 320 to a negative

-282 + (-20,320) = -20,602

tatuchka [14]4 years ago
5 0
Negative two hundred eighty-two

Negative twenty thousand three hundred twentt
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Tell whether the shapes are similar explain your answer
Luda [366]
Yes you can assume they are similar because the sides that correspond with one another are half of the big triangles measurements. 16/2=8 12/2=6 etc.
7 0
3 years ago
If your monthly income is $300 and you spend $50 on clothes, what percent of your monthly budget is spent on clothing
nata0808 [166]
Here is the answer to the problem above. So, if the monthly income is $300 and $50 was spent on clothing, we will find the percentage of $50 from $300 by dividing 50 by 300 then multiply the quotient by 100. So the answer is 16.67%. So the answer is 16.67%. Hope this answers your question.
3 0
3 years ago
Read 2 more answers
Ying Zyiyu covered the first 300 miles of a trip going at 60 mph and the last hundred going at 40 mph. What was his average spee
Tomtit [17]

Answer:

53.33mph

Step-by-step explanation:

Let's calculated the total time spent on the journey first;

For the first 300miles the time spent is ;

From Distance = speed× time

time = Distance/ speed

= 300/60 = 5 hours

Similarly for the last 100mile the time taken is ;

100/40 = 2.5 hours

Total time spent = 5 +2.5 = 7.5 hours

Total distance covered 400miles

Therefore average speed = 400/7.5 =53.33mph

8 0
3 years ago
The partial pressure of oxygen PaO2 is a measure ofthe amount of oxygen in the blood. Assume that the distribution ofPaO2 levels
Rus_ich [418]

Answer: a) 0.8665

b) 0.8190

Step-by-step explanation:

Given : The partial pressure of oxygen PaO2 is a measure ofthe amount of oxygen in the blood. Assume that the distribution ofPaO2 levels among newborns has a \mu=38 mmHg and \sigma= 9 mmHg.

If we take a random sample n= 25 newborns, then  using formula z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}, we have

At x= 36

z=\dfrac{36-38}{\dfrac{9}{\sqrt{25}}}\approx-1.11

At x= 41

z=\dfrac{36-38}{\dfrac{9}{\sqrt{25}}}\approx1.67

Using table for z-values, the probability that the sample mean will be greater than 36 :

P(z>-1.11)=1-P(\leq-1.11)=1-(1-P(z\leq1.11))=P(z\leq1.11)=0.8665004\approx0.8665

The probability that the sample mean will be between 36 and 41 :-

P(-1.11

4 0
3 years ago
a wildlife manager determines that the function y=200x1.07* represents the deer population at a state park x years after the pop
Kobotan [32]

Answer:

Table:

0,200

4, 262

8,344

12, 450

Population after 12 years is 450 deer

Initial population is 200 deer.

Step-by-step explanation:

You take the x in the table and plug it in as an exponent so you will need a calculator or multiple the 1.07 by that many times so 1.07 12 times multipled by itself. and the initial is 0 years so anything to the exponent of 0 is 1 so that show i got 200 for the x=0

8 0
3 years ago
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