2 years ago

Use the formula A = bh, where A is the area, b is base length, and H is the height of the parallelogram, to solve this problem.

Mathematics

1 answer:

klemol [59]2 years ago

8 0

Answer:

45 in

(1440 / 32)

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3 years ago

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The two figures are similar. Find the ratios (red to blue) of the perimeters and of the areas. Write the ratios as fractions in

vesna_86 [32]

Answer:

see explanation

Step-by-step explanation:

The perimeters of the similar figures have the same ratio as the sides.

ratio of perimeters = $\frac{11}{6}$

ratio of areas = 11² : 6² , that is 121 : 36

ratio of areas = $\frac{121}{36}$

3 0

3 years ago

Can someone please explain how to solve this? And give me the answer?! THANK U !

Lyrx [107]

we know the segment QP is an angle bisector, namely it divides ∡SQR into two equal angles, thus ∡1 = ∡2, and ∡SQR = ∡1 + ∡2.

$\bf \begin{cases} \measuredangle SQR = \measuredangle 1 + \measuredangle 2\\\\ \measuredangle 2 = \measuredangle 1 = 5x-7 \end{cases}\qquad \qquad \stackrel{\measuredangle SQR}{7x+13} = (\stackrel{\measuredangle 1}{5x-7})+(\stackrel{\measuredangle 2}{5x-7}) \\\\\\ 7x+13 = 10x-14\implies 13=3x-14\implies 27=3x \\\\\\ \cfrac{27}{3}=x\implies 9=x \\\\[-0.35em] ~\dotfill\\\\ \measuredangle SQR = 7(9)+13\implies \measuredangle SQR = 76$