Answer:
The correct answer is 2.67 ATP per molecule.
Explanation:
With the help of sucrose, it comes to known that the dissociation of a sugar-sugar bond generates one phosphorylated monosaccharide. Therefore, raffinose, which is a trisaccharide exhibits bonds of two sugar-sugar molecules. Post dissociation, they will generate one regular monosaccharide and two phosphorylated monosaccharides.
There will be the generation of net ATPs by each phosphorylated monosaccharide as they are already phosphorylated. While the regular monosaccharide, which is first needed to get phosphorylated will only produce two ATPs. Thus, a total of 8 ATPs will be produced by one molecule of raffinose. After dividing by three monosaccharides, the molecule will produce 8/3 = 2.67 ATPs per monosaccharide.
Answer:
0%
Explanation:
This involves a single gene coding for melanin pigment in the skin. The recessive form of this gene (allele) is albinism while the dominant form is a normal skin. The question highlights that the normal male parent (dominant) has no family history of albinism, this means that nobody in their family has ever possessed albinism or has been a carrier/heterozygous for the trait. This is because a carrier/heterozygote will always produce the recessive trait (albinism) if crossed with another carrier or albino individual.
In a nutshell, the normal male parent is homozygous for the dominant trait. Hence, if a homozygous dominant male is crossed with an albino woman (homozygous recessive), all their offsprings will possess a heterozygous genotype and dominant phenotype. Meaning that none of their children will ba an albino.
Hence, the percentage of their child being an albino is 0.
The answer to your question is : Aspirin, Codeine, & Ephedrine!
They will be genetically identical to the daughter cells.
