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Westkost [7]
2 years ago
13

Use the data to answer the question. Which statement best describes the data?

Physics
1 answer:
Natasha2012 [34]2 years ago
7 0

A statement which best describes the data is that: C. they are precise and reproducible.

<h3>What is an experiment?</h3>

An experiment can be defined as a scientific investigation which typically involves the process of manipulating an independent variable (the cause), so as to determine or measure the dependent variable (the effect).

<h3>What is data?</h3>

Data can be defined as a representation of instructions or factual information in a formalized manner, especially as a series of binary digits (bits) or samples that are used by scientist in an experiment or research.

<h3>The types of data.</h3>

Generally, there are two (2) main types of data and these include:

  • Primary data
  • Secondary data

Based on the data provided in the table (see attachment), we can infer and logically deduce that a statement which best describes the data is that they are precise and reproducible.

Read more on experiments here: brainly.com/question/25322325

#SPJ1

Complete Question:

Which statement best describes the data?

A. They are accurate and reproducible.

B. They are accurate but not reproducible.

C. They are precise and reproducible.

D. They are precise but not reproducible.

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A car starts from rest and accelerates to 14 m/s in 2 seconds. What was its acceleration
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Answer:

7m/s^2

Explanation:

using v=u+at

since the car started from rest, u=0 , v=14m/s t=2s

a =acceleration.

14=0+a×2

14=0+2a

14=2a

a= 14/2 =7

a=7m/s^2

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3 years ago
How far has a ball traveled after 3.6 seconds when thrown downward at a<br> velocity 3.75 m/s?
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ball traveled 13.5 m/s after 3.6 seconds

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A 26 foot ladder is lowered down a vertical wall at a rate of 3 feet per minute. The base of the ladder is sliding away from the
lakkis [162]

Answer:

(i) 7.2 feet per minute.

(ii) No, the rate would be different.

(iii) The rate would be always positive.

(iv) the resultant change would be constant.

(v) 0 feet per min

Explanation:

Let the length of ladder is l, x be the height of the top of the ladder from the ground and y be the length of the bottom of the ladder from the wall,

By making the diagram of this situation,

Applying Pythagoras theorem,

l^2 = x^2 + y^2-----(1)

Differentiating with respect to t ( time ),

0=2x\frac{dx}{dt} + 2y\frac{dy}{dt}  ( l = 26 feet = constant )

\implies 2y\frac{dy}{dt} = -2x\frac{dx}{dt}

\implies \frac{dy}{dt}=-\frac{x}{y}\frac{dx}{dt}

We have,

y = 10, \frac{dx}{dt}= -3\text{ feet per min}

\frac{dy}{dt}=\frac{3x}{10}-----(X)

(i) From equation (1),

26^2 = x^2 + 10^2

676=x^2 + 100

576 = x^2

\implies x = 24\text{ feet}

From equation (X),

\frac{dy}{dt}=\frac{3\times 24}{10}=7.2\text{ feet per min}

(ii) From equation (X),

\frac{dy}{dt}\propto x

Thus, for different value of x the value of \frac{dy}{dt} would be different.

(iii) Since, distance = Positive number,

So, the value of y will always a positive number.

Thus, from equation (X),

The rate would always be a positive.

(iv) The length of the ladder is constant, so, the resultant change would be constant.

i.e. x = increases ⇒ y = decreases

y = decreases ⇒ y = increases

(v) if ladder hit the ground x = 0,

So, from equation (X),

\frac{dy}{dt}=0\text{ feet per min}

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