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liraira [26]
3 years ago
10

4) Astronomers use tiny wobbles of distant stars to detect the presence of planets orbiting those stars. This occurs because the

star exerts a gravitational pull on the planet while the planet A) repels the star it orbits. B) exerts no force on the star. C) creates friction between itself and the star. D) exerts a gravitational pull on the star it orbits.
Physics
1 answer:
liq [111]3 years ago
8 0
<span>Astronomers use tiny wobbles of distant stars to detect the presence of planets orbiting those stars. This occurs because the star exerts a gravitational pull on the planet while the planet  D) exerts a gravitational pull on the star it orbits.</span>
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The perceived loudness of a sound is measured in
diamong [38]
<h2>Answer: decibels </h2>

The decibel dB is the relation between two values: the pressure produced by a sound wave and a pressure taken as a reference. Resulting in a dimensionless value.

It should be noted that itself<u> is not a unit of measure</u>, since in reality the unit is bel B (which <u>is not part of the International System of Units</u>) in honor of Alexander Graham Bell.

However, given the amplitude of the measured elements in practice, its submultiple, the decibel, is used. That is, this quotient is a logarithmic expression, where 1dB=0.1B

5 0
3 years ago
A student claims "everything falls at the same acceleration rate on the Moon, where there is no air or friction," how would you
Alexeev081 [22]

Now let’s say you’re on the Moon. If you were to drop a hammer and a feather from the same height, which would hit the ground first?

Trick Question! On the moon both objects would hit the ground at the same time. On Earth, the hammer lands first.

So yeah, the student is right. Galileo gave us this theory long ago.

5 0
3 years ago
A 2.0-kg object moving with a velocity of 5.0 m/s in the positive x direction strikes and sticks to a 3.0-kg object moving with
Andrej [43]

Answer:

5.4 J.

Explanation:

Given,

mass of the object, m = 2 Kg

initial speed, u = 5 m/s

mass of another object,m' = 3 kg

initial speed of another orbit,u' = 2 m/s

KE lost after collusion = ?

Final velocity of the system

Using conservation of momentum

m u + m'u' = (m + m') V

2 x 5 + 3 x 2 = ( 2 + 3 )V

16 = 5 V

V = 3.2 m/s

Initial KE = \dfrac{1}{2}mu^2 + \dfrac{1}{2}m'u'^2

              = \dfrac{1}{2}\times 2\times 5^2 + \dfrac{1}{2}\times 3 \times 2^2

              = 31 J

Final KE = \dfrac{1}{2} (m+m')V^2 = \dfrac{1}{2}\times 5 \times 3.2^2 = 25.6 J

Loss in KE = 31 J - 25.6 J = 5.4 J.

4 0
3 years ago
The formation of condensation on a glass of ice water causes the ice to melt faster than it would otherwise. If 8.55 g of conden
SSSSS [86.1K]

Answer:

m = 62.14 g

Explanation:

Energy used to melt the ice is the energy released by the condensation of the water forms on the glass

so here we have

energy for the condensation of water is given as

let mass of water condensed = m

E = m_1 L_f

now the energy of vaporization is given as

E = m_2 L_v

here we know that

L_f = 79.8 kCal/kg

L_v = 580 k Cal/kg

Now we have

8.55 \times 580 = m \times 79.8

m = 62.14 g

3 0
3 years ago
A 250 - ω resistor is connected in series with a 4.80 - μf capacitor. the voltage across the capacitor is vc=(7.60v)⋅sin[(120rad
galben [10]
<span>553 ohms The Capacitive reactance of a capacitor is dependent upon the frequency. The lower the frequency, the higher the reactance, the higher the frequency, the lower the reactance. The equation is Xc = 1/(2*pi*f*C) where Xc = Reactance in ohms pi = 3.1415926535..... f = frequency in hertz. C = capacitance in farads. I'm assuming that the voltage and resistor mentioned in the question are for later parts that are not mentioned in this question. Reason is that they have no effect on the reactance, but would have an effect if a question about current draw is made in a later part. With that said, let's calculate the reactance. The 120 rad/s frequency is better known as 60 Hz. Substitute known values into the formula. Xc = 1/(2*pi* 60 * 0.00000480) Xc = 1/0.001809557 Xc = 552.6213302 Rounding to 3 significant figures gives 553 ohms.</span>
6 0
3 years ago
Read 2 more answers
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