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3 years ago

In your own words explain Newton’s law of universal gravitation?

2 answers:

5 0

The Law of Universal Gravitation

- Gravity is an attractive force that pulls two objects toward one another.
Gravity is stronger coming from heavy objects when compared to light objects. The force of gravity weakens as the distance between objects increases.

- All objects in the universe feel the effects of gravity. Us humans feel the Earth’s gravitational pull towards its center. The Sun, which is larger than the other planets, pulls all of them toward itself, and each planet pulls back against the Sun. Since they are much smaller than the Sun, their pull is much weaker.

- Humans have a gravitational pull toward other humans, but it is weak and not noticeable. Therefore, the force of gravity diminishes with the decrease in size.

aivan3 [116]3 years ago

3 0

The force due of attraction between two bodies is proportional to the mass of both objects but inversely proportional to the square of the distance between them.

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You drive in a straight line at 22 m/s for 12 miles, then at 30 m/s for another 12 miles. (a) How does your average speed sav co

Setler [38]

Answer:

Explanation:One method of calculating average speed is to divide the total distance by the total time spent

d1=d2= 12 miles

d1=d2= 19312.1 m

$t1=\frac{d1}{u1} \\t1=19312.1/22\\t1=877.8 secs$

$t2=\frac{d2}{u2} \\t2=19312.1/30\\t2=673.7 secs$

$u_a=\frac{d1+d2}{t1+t2} \\u_a=25.385 m/s$

There is slight difference between the average speeds due to the reason that average speed is not just the midpoint of the speed but is the total distance traveled by total time.

6 0

3 years ago

Venus has an average distance to the sun of 0.723 AU. In two or more complete sentences, explain how to calculate the orbital pe

Mice21 [21]

As per the question the distance of venus from sun is given as 0.723 AU

We have been asked to calculate the time period of the planet venus.

As per kepler's laws of planetary motion the square of time period of planet is directly proportional to the cube of semi major axis. mathematically

$T^{2} \alpha R^{3}$

⇒ $T^{2} = KR^{3}$ where is k is the proportionality constant

We may solve this problem by comparing with the time period of the earth . We know that time period of earth is 365.5 days

Hence $T_{1} =365.5 days$

The distance of sun from earth is taken as 1 AU i.e the mean distance of earth from sun

Hence $R_{1} =1 AU$

The distance of venus from sun is 0.723 AU i.e $R_{2} =0.723$

From keplers law we know that- $\frac{T_{1} ^{2} }{T_{2} ^{2} } =\frac{R_{1} ^{3} }{R_{2} ^{3} }$

⇒ $T_{2} ^{2} =T_{1} ^{2} *\frac{R_{2} ^{3} }{R_{1} ^{3} }$

Putting the values mentioned above we get-

$T_{2} ^{2} =50,350.132851075$

⇒ $T_{2} =\sqrt{50,350.132851075}$

⇒ $T_{2} = 224.388352752710 days.$

Hence the time period of venus is 224.388352752710 days

7 0

4 years ago

Read 2 more answers

Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 5.00 m above

GenaCL600 [577]

Answer:

g = 15.5 m/s²

Explanation:

In order to find the acceleration due to gravity near the surface of this planet can be calculated by using 2nd equation of motion. The 2nd equation of motion is given as:

h = Vi t + (0.5)gt²

where,

h = height covered by the wrench = 5 m

Vi = Initial Velocity = 0 m/s

t = Time Taken to hit the ground = 0.804 s

g = acceleration due to gravity near the surface of the planet = ?

Therefore,

5 m = (0 m/s)(0.804 s) + (0.5)(g)(0.804 s)²

g = (5 m)/(0.3232 s²)

4 0

4 years ago

Dump Tower is 96 stories tall. A small, 1.2-kg object is dropped over the side of the roof of the tower and accelerates toward t

laiz [17]

Answer:

6.0 s

98 m/s

Explanation:

The radius of the planet is much bigger than the height of the tower, so we will assume the acceleration is constant. Neglect air resistance.

Acceleration due to gravity on this planet is:

a = GM / r²

a = (6.67×10⁻¹¹ m³/kg/s²) (2.7 × 1.48×10²³ kg) / (1.7 × 750,000 m)²

a = 16.4 m/s²

The height of the tower is:

Δy = 96 × 3.05 m

Δy = 293 m

Given v₀ = 0 m/s, find t and v.

Δy = v₀ t + ½ at²

(293 m) = (0 m/s) t + ½ (16.4 m/s²) t²

t = 6.0 s

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (16.4 m/s²) (293 m)

v = 98 m/s

8 0

4 years ago

Why is the power of concave lense negative

Travka [436]

Answer:

because the focal length is negative.

Explanation:

Power of a lens (P) is the reciprocal of its focal length (f).

4 0

3 years ago