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kirza4 [7]
3 years ago
9

9. Electron travelling though two horizontal plates

Physics
1 answer:
VLD [36.1K]3 years ago
6 0

Answer:

;

Explanation:

;

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The water passing over victoria falls, located along the zambezi river on the border of zimbabwe and zabia drops about 105 m. Ho
7nadin3 [17]

Answer:

1029 Jkg⁻¹

Explanation:

h = height dropped by the water falling = 105 m

g = acceleration due to gravity = 9.8 ms⁻²

m = mass of water

Using conservation of energy, the internal energy produced is same as the gravitational potential energy lost, hence

Internal energy = Gravitational potential energy

U = mgh \\\frac{U}{m} = gh\\\frac{U}{m} = (9.8) (105)\\\frac{U}{m} = 1029 Jkg^{-1}

7 0
4 years ago
A 15 kg cart is pushed on a frictionless surface from rest horizontally by a 30 N force. What is the cart's acceleration?
Rainbow [258]

Answer:

<em>a. The cart's acceleration is 2 m/s^2</em>

<em>b. The cart will travel 100 m</em>

<em>c. The speed is 20 m/s</em>

Explanation:

a. The acceleration of the cart can be calculated using Newton's second law:

F = m.a

Solving for a:

\displaystyle a=\frac{F}{m}

The cart has a mass of m=15 Kg and is applied a net force of F=30 N, thus:

\displaystyle a=\frac{30}{15}

a=2\ m/s^2

b.

Now we use kinematics to find the distance and speed:

\displaystyle x = v_o.t+\frac{at^2}{2}

The cart starts from rest (vo=0). The distance traveled in t=10 seconds is:

\displaystyle x = 0*10+\frac{2*10^2}{2}

x = 100\ m

The cart will travel 100 m

c.

The final speed is calculated by:

v_f=0+2*10=20\ m/s

The speed is 20 m/s

5 0
3 years ago
I am a bit confused about this question.
gavmur [86]

How do you know when something is moving ?  You ALWAYS have to compare it to something else.  If the object in question changes its distance or direction from your house, or from your big toe, or from a stake in the ground in your front yard, then you say it's moving.  The thing is:  There's ALWAYS something else to compare it to.

I assume you're sitting on the couch now, staring at the TV, or at your computer, or at your phone.  Compared to the couch, or to the tree in your front yard, or to somebody sitting on top of Mt. Everest, or to downtown Jerusalem, you're NOT moving.  Your distance and direction from the reference point isn't changing.

BUT ... what if you compare yourself to somebody sitting at the North pole of the Sun ?  He has to keep turning his eyes to watch you (because the Earth including you is in orbit around the sun).  So your direction from him keeps changing, and 'relative' to him (compared to him), you're definitely moving.

Now let's go a little farther:  

You're sitting in a comfy seat, reading a book that's in your lap.  Maybe you're even getting sleepy.  You're sitting still in the seat, and the book in your lap isn't moving.

SURPRISE !  Your comfy seat is in Row-27 of a passenger jet, and you're flying to Seattle to visit your Grandma.  right now, you're just passing over Casper, Wyoming, and there's somebody down on the ground playing with a telescope.  He looks at your airplane, and HE says that you, the seat you're sitting in, and your book are ALL moving at almost 500 miles an hour.

The difference is:  YOU're comparing your book to the seat in front of you, and YOU say the book is not moving.  The guy with the telescope is comparing the book to the ground he's standing on, and HE says your book is moving west at 500 miles an hour.

You're BOTH correct.  The description of ANY motion always depends on what you're comparing to.  If you're about to ask "What's the REAL motion of the book ?", then I'm sorry.  There's NO SUCH THING as 'REALLY'.  It always depends on what you're comparing to.  Nine people can be watching the same object, and they can have nine different descriptions of its motion, and they're ALL correct.  They're just comparing the object to different things in their own neighborhood, and the nine things are all moving in different ways.

The bottom line:  MOTION IS ALWAYS RELATIVE (to something else).

8 0
3 years ago
A stationary 500 kg tank fires a 20 kg miegile at 100 m/s. What is the velocity of the tank after the missile is fired? Assume t
dedylja [7]

Answer:

v₁ = 4 [m/s].

Explanation:

This problem can be solved by using the principle of conservation of linear momentum. Where momentum is preserved before and after the missile is fired.

P=m*v

where:

P = linear momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

(m_{1}*v_{1})=(m_{2}*v_{2})

where:

m₁ = mass of the tank = 500 [kg]

v₁ = velocity of the tank after firing the missile [m/s]

m₂ = mass of the missile = 20 [kg]

v₂ = velocity of the missile after firing = 100 [m/s]

(500*v_{1})=(20*100)\\v_{1}=2000/500\\v_{1}=4[m/s]

8 0
3 years ago
If the weight of an object that is submerged in a fluid is 10 N and the buoyant force on it is
Nady [450]

Answer: the object should be overcome by buoyancy and rise in the fluid.

Explanation:

5 0
3 years ago
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