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kirza4 [7]
3 years ago
9

9. Electron travelling though two horizontal plates

Physics
1 answer:
VLD [36.1K]3 years ago
6 0

Answer:

;

Explanation:

;

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On the moon, the acceleration of gravity is 1.6 m/s2. If an object has a
Amanda [17]

Answer:

5.1 kg

Explanation:

Its mass on the moon is 5.1 kg because mass is an intrinsic property of a material and does not change with location. Although, its weight might vary because its acceleration of gravity g is dependent on the mass M and radius r of the planet(in this case, moon) involved g = GM/r². Since weight W = mg is dependent o g, weight varies but mass remains constant.

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3 years ago
A solenoidal coil with 25 turns of wire is wound tightly around another coil with 310 turns. the inner solenoid is 25.0 cm long
Ymorist [56]
(a) Image 1
(b) Image 2
(c) Image 3

6 0
3 years ago
A 11kg block slides up a 30° inclined plane at a constant velocity. The coefficient of friction between the block and the plane
astra-53 [7]

Answer:

The magnitude of the applied force is 94.74 N

Explanation:

Mass of the block, m = 11 kg

Angle of inclination of the plane, \theta = 30^{\circ}

Friction coefficient, \mu_{k} = 0.2

Now,

Normal force that acts on the block is given by:

F_{N} = mgcos\theta + Fsin\theta           (1)

Now, to maintain the equilibrium parallel to ramp the forces must be balanced.

Thus

Fcos\theta = \mu_{k}F_{N}                       (2)

From eqn (1) and (2)

Fcos\theta = \mu_{k}(mgcos\theta + Fsin\theta)

F(cos\theta - \mu_{k}sin\theta) = \mu_{k}mgcos\theta

F = \frac{\mu_{k}mgcos\theta}{cos\theta - \mu_{k}sin\theta}

F = \frac{0.2\times 11\times 9.8cos30^{\circ}}{cos30^{\circ} - 0.2\times sin30^{\circ}}

F = 94.74 N

3 0
3 years ago
Calculate work when the force exerted to push an object is 75 n and the distance is 1.2 kilometers.
grigory [225]

The magnitude of the work done to push the object is 90,000 J

<h3>When is Work done on a body ?</h3>

Work is done on a body when the direction of the force applied is parallel to the direction of the displacement of the body.

The following parameters are given;

  • Force F = 75 N
  • Distance S = 1.2 Km
  • Work W = ?

First convert the distance in kilometer to meter by multiplying it by 1000

S = 1.2 x 1000 = 1200 m

From the definition of work,

W = F x S

Substitute the parameters into the formula

W = 75 x 1200

W = 90,000 J

Therefore, the magnitude of the work done to push the object is 90,000 J

Learn more about Work here: brainly.com/question/25573309

#SPJ1

7 0
1 year ago
I really need help i’m in a really big rush
kompoz [17]


1. The speed is at a constant rate same with the acceleration and velocity

2. When there getting close to the top there speed, acceleration, and velocity all start to decrease

3. The speed and acceleration and velocity all on the way down drastically increase number

hope I helped
3 0
2 years ago
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