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tigry1 [53]
1 year ago
11

Combine like terms to create an equivalent expression.

Mathematics
1 answer:
Lelu [443]1 year ago
5 0

Answer:

\frac{1}{6} p - \frac{4}{5}

Step-by-step explanation:

collect like terms

- \frac{2}{3} p + \frac{5}{6} p + \frac{1}{5} - 1

= - \frac{2(2)}{2(3)} p + \frac{5}{6} p + \frac{1}{5} - \frac{5}{5}

= - \frac{4}{6} p + \frac{5}{6} p - \frac{4}{5}

= \frac{1}{6} p - \frac{4}{5}

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Is this a function <br><br> Find the domain and range
Novay_Z [31]

Answer:

Yes

Domain: 1, -1, 0, -3, 3

Range: 1, -1, 6

Step-by-step explanation:

The domain is in the left oval, the range is in the right oval. To find if its a function you have to make sure the domain (left side) doesn't "cheat". One number in the domain cant have more than one number in the range (right side), BUT (for future reference) the range can cheat. As shown, the right side numbers 1 and 6 have two different arrow pointed at them. As long as the domain doesnt "cheat" it is a function

8 0
3 years ago
sarah invests £9600 at a simple interest rate of 8% per year. Work out the value of the investment after 3 years
andre [41]

Answer:

the value of the investment after 3 years=  £11,904

Step-by-step explanation:

sarah invests £9600 at a simple interest rate of 8% per year

number of years = 3

Formula for simple interest

I = P*n* r

P is the initial amount invested= 9600

r is the rate of interest = 8% = 0.08

n = number of years = 3

Now we find interest using formula

I = 9600 * 0.08 * 3= 2304

Interest amount is 2,304

Now we add the interest with the initial amount to get the value of investment after 3 years

9600 + 2304= 11904

6 0
3 years ago
W
Lemur [1.5K]

Answer:

B. 74 / 100

Explanation:

I got it right on the test :)

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Answer:

15

Step-by-step explanation:

Hoped it helped

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