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Iteru [2.4K]
4 years ago
11

The lock on a safe requires a three-digit code to open it. The three digits must each be a number from 0-9 (10 possible numbers)

. Each number cannot be used more than once in the code. How many codes could there be?
A.1,000
B.720
C.30
D.120
Mathematics
1 answer:
vovangra [49]4 years ago
7 0
The correct answer is Choice B: 720.

To solve this, you have to use the Fundamental Counting Principal. You find the total number of options for each of the digits, then multiply them together.

For the first one, there are 10 options, then 9 options and finally 8 options.

10 x 9 x 8 = 720
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A product is now £50, the product was reduced by 20%, what was the original price
olga nikolaevna [1]

the original price is "x", or 100%.

but we know that if we reduce "x" by 20%, namely 100% - 20% = 80%, the 80% of "x" is really £50, what is "x" or the 100% anyway?

\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 50&80 \end{array}\implies \cfrac{x}{50}=\cfrac{100}{80}\implies \cfrac{x}{50}=\cfrac{5}{4}\implies 4x=250 \\\\\\ x=\cfrac{250}{4}\implies x=62.5

3 0
3 years ago
Evaluate the following expression when x = -1, y = 2, z = -3, and<br> w = 4.<br> x² - y²
vaieri [72.5K]

Answer:

-3

Step-by-step explanation:

-1*-1=1

2*2=4

1-4

=-3

7 0
3 years ago
What is 1 1/8 as a decmia
tensa zangetsu [6.8K]
Do you mean as a decimal? 11.8
8 0
3 years ago
What numbers less than 200 are divisble by 4 but not 12
kolezko [41]

Answer:

There are 48 numbers that satisfy the condition

Step-by-step explanation:

Find the relationship between 3 and 12

3 * 4 = 12

The maximum number of multiples of 12 within 200 is 18.

The maximum number of multiples within 200 is 66.

So the number of numbers within 200 that go exactly into 3 but not exactly into 12 is:

66-18 = 48

3 0
3 years ago
Is (2, 3) a solution to the inequality y &gt; 6x + 3?
Sindrei [870]

Good morning

Answer:

NO

Step-by-step explanation:

Here we just substitute x and y by their values and see if the inequality still true or not

y = 3

6x + 3 = 6(2) + 3 = 15

since 3 < 15 then the inequality y > 6x + 3 is wrong.

______________________________________

:)

8 0
4 years ago
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