Answer:
g/cm²
Step-by-step explanation:
First, we need to find the volume of the prism. The volume of a square pyramid is V = Bh/3
B = 100 cm²
h = 6 cm
V = 100 cm² * 6 cm /3
V = 600 cm³ /3
V = 200 cm³
Next, we need to solve for the density based on the desired volume and mass.
m = mass = 300 g
V = volume
density = m/V
density = 300 g / 200 cm³
density = 3/2 g/cm³
The lowest possible density of the material to make the paperweight would be g/cm²
The slope of the parallel line is -6/7
the slope of the perpendicular line is 7/6
the slope of the line = -6/7
the gradient of two parallel lines are equal
the product of the gradient of two perpendicular lines is -1
: the gradient m1*m2 = -1
m2= -1(-6/7)
m2= 7/6
<h2><em>we can write (3x^2-5y^2) as (3x-5y)^2</em></h2><h2><em>(
3
x
−
5
y
)
2 as (
3
x−
5
y
)
(
3
x−
5
y
)</em></h2><h2><em>3
x
(
3
x
−
5
y
)
−
5
y
(
3x
−5
y
)</em></h2><h2><em>3
x
(
3
x
−
5
y
)
−
5
y
(3
x
−
5
y
)</em></h2><h2><em>3
x
(
3
x
)
+
3
x
(
−
5y
)
−
5
y
(
3
x
)
−
5
y(
-5
y
)</em></h2><h2><em>9
x
2
−
15
x
y
−
15y
x
+
25
y
2
</em></h2><h2><em> Subtract 15
y
x from −
15
x
y
.</em></h2><h2><em>9
x
2
−
30
xy
+
25
y
2</em></h2><h2><em> HOPE IT HELPS(◕‿◕✿) </em></h2><h2><em> SMILE!! </em></h2>
Answer:
37.5
Step-by-step explanation:
Answer:
Step-by-step explanation:
Don't use 0 as a substitute for θ. 0 is always 0.
cosθ = -5/(2√15)
secθ = 1/cosθ = -2√15/5
