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ololo11 [35]
4 years ago
5

The length of the hypotenuse of a right triangle is 4.5 inches. The length of one of the legs is 2.7 inches. What is the length

of the other leg of the triangle?
A. 1.8 in.
B. 3.6 in.
C. 5.2 in
D. 7.2 in.
Mathematics
1 answer:
cupoosta [38]4 years ago
3 0

Answer:

B. 3.6 inches

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The right answer is A. AA Postulate

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2 years ago
Find the x- and y- intercepts of parabola y=5x^2-16x+10
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Y-INTERCEPT

y = 5x^2 - 16x + 10

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0

We need to use the quadratic formula

The quadratic formula helps us find what values of x make the equation = 0

Quadratic formula: x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\

The x-intercepts are at:

(\frac{8 + \sqrt{14}}{5}, 0)\\(\frac{8 - \sqrt{14}}{5}, 0)

5 0
2 years ago
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w - 3.3 + -3.3 = 5.6 - 3.3

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3 years ago
Which equation gives the number of 1/4 centimeter that are in 7/8 centimeter?
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The answer is B.

remember to use the reciprocal when dividing with fractions
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