Answer:
![4ln [\frac{x^2 (x^3-1)}{x-5}]](https://tex.z-dn.net/?f=%204ln%20%5B%5Cfrac%7Bx%5E2%20%28x%5E3-1%29%7D%7Bx-5%7D%5D)
Step-by-step explanation:
For this case we have the following expression:
![4[ln(x^3-1) +2ln(x) -ln(x-5)]](https://tex.z-dn.net/?f=%204%5Bln%28x%5E3-1%29%20%2B2ln%28x%29%20-ln%28x-5%29%5D)
For this case we can apply the following property:
And we can rewrite the following expression like this:
And we can rewrite like this our expression:
![4[ln(x^3-1) +ln(x^2) -ln(x-5)]](https://tex.z-dn.net/?f=%204%5Bln%28x%5E3-1%29%20%2Bln%28x%5E2%29%20-ln%28x-5%29%5D)
Now we can use the following property:
And we got this:
![4[ln(x^3-1)(x^2) -ln(x-5)]](https://tex.z-dn.net/?f=%204%5Bln%28x%5E3-1%29%28x%5E2%29%20-ln%28x-5%29%5D)
And now we can apply the following property:
And we got this:
And that would be our final answer on this case.
Step-by-step explanation:
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PAGAL KUTTA
Answer:
The sixth term of the binomial expansion is;
10C5 (5y)^5 (3)^5
Step-by-step explanation:
Here, we want to select which of the options represent the 6th term of the binomial expansion;
(5y + 3)^10
We should know that while the powers of 5y will be increasing, the powers of 3 will be decreasing.
We can write the terms as follows;
10C0(5y)^10(3)^0 + 10C1(5y)^9(3)^1 + 10C2(5y)^
8(3)^2 + 10C3(5y)^7(3)^3 + 10C4(5y)^6(3)^4 + 10C5(5y)^5(3)^5 + ............
Answer:
146 minus 59? equals 87 :)
both had differences in geometry
