Considering that the powers of 7 follow a pattern, it is found that the last two digits of are 43.
<h3>What is the powers of 7 pattern?</h3>
The last two digits of a power of 7 will always follow the following pattern: {07, 49, 43, 01}, which means that, for , we have to look at the remainder of the division by 4:
- If the remainder is of 1, the last two digits are 07.
- If the remainder is of 2, the last two digits are 49.
- If the remainder is of 3, the last two digits are 43.
- If the remainder is of 0, the last two digits are 01.
In this problem, we have that n = 1867, and the remainder of the division of 1867 by 4 is of 3, hence the last two digits of are 43.
More can be learned about the powers of 7 pattern at brainly.com/question/10598663
A. This is an example of a situation making use of the concept of Fundamental Principles of Counting. On the first spot, Sam may choose from the five available flags. On the next spot, he can only choose from four flags. This goes on until no more flag is left. For short, there are 5! ways. This is equal to 120.
b. Since only 3 out of the five flags can be used and the arrangement is important, make use of Permutation. The answer is 5P3 = 60. There are 60 ways.
The correct answer to your question is B.
Answer:
a and d
Step-by-step explanation:
Answer:
There are 81 band members. :-)
Step-by-step explanation:
4 rows of 20 = 80 ... with one left over = 80 + 1 (81)
6 rows of 13 = 78 ... with three left over = 78 + 3 (81)
7 rows of 11 = 77 ... with four left over = 77 + 4 (81)