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Sergio039 [100]
2 years ago
8

When the shape of a bst approaches that of a perfectly balanced binary tree, what is the worst case performance characteristic o

f searches and insertions?
Mathematics
1 answer:
irga5000 [103]2 years ago
7 0

The shape of a bst approaches that of a perfectly balanced binary tree, (log2n) is the time complexity for a balanced binary search tree in case of insertions and search.

In computing, binary bushes are mainly used for looking and sorting as they offer a way to save statistics hierarchically. a few common operations that may be conducted on binary trees encompass insertion, deletion, and traversal.

A binary tree has a special situation that each node could have a most of two youngsters. A binary tree has the benefits of each an ordered array and a linked listing as search is as brief as in a taken care of array and insertion or deletion operation are as fast as in related listing.

In pc science, a binary tree is a tree information shape in which every node has at maximum two youngsters, that are known as the left baby and the proper toddler.

Learn  more about binary trees here brainly.com/question/16644287

#SPJ4

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The life expectancy in the US is 75 with a standard deviation of 7 years. A random sample of 49 individuals is selected. What is
victus00 [196]

Answer:

0.02275

Step-by-step explanation:

We use this z score formula to solve for this question

z-score is is z = (x-μ)/σ/√n

where x is the raw score

μ is the population mean

σ is the population standard deviation

From the above question,

x = 77

μ = 75

σ = 7

number of samples = 49

Hence, the z score = 77 - 75/ (7/√49)

= 2/(7/7)

= 2/1

= 2

Hence, the z score = 2

Using the z table to find probability

P(x<77) = 0.97725

P(x>77) = 1 - P(x<77)

= 1 - 0.97725

= 0.02275

Therefore, the probability that the same mean will be larger than 77 years

is 0.02275

7 0
2 years ago
Expanded form of 164.38
Sauron [17]

164.38 = (1 x 100) + (6 x 10) + (4 x 1) + (3/10) + (8/100)

7 0
3 years ago
Read 2 more answers
The mean weight 20 students in a room is 65 kg one student one student who weight is 88kg went into the room what is the new mea
umka2103 [35]

The new mean is 66.09

<u>Explanation:</u>

Mean weight of 20 students = 65kg

One student with 88kg entered the room.

New mean = ?

\frac{x_1+x_2+....+x_2_0}{20} = 65

\frac{x_1+x_2+....+x_2_0 + 88}{21} = ?

The above equation can further be written as:

x_1 + x_2 +....+x_2_0 = 65 X 20\\\\x_1 + x_2 +....+x_2_0 = 1300

New mean = \frac{1300 + 88}{21}

                 = 66.09

Therefore, the new mean is 66.09

6 0
2 years ago
What is 7/5 into a mixed number?
Varvara68 [4.7K]

Answer:

improper fraction: 7/5

mixed number: 1 2/5

8 0
2 years ago
Read 2 more answers
Solve the equation -25p – 2 = 48 for p.<br><br> A. -2<br> B. 1<br> C. 3<br> D. 8
konstantin123 [22]

Answer:

A. -2

Step-by-step explanation:

-25p - 2 = 48

First, add 2 to both sides

That gives you

-25p = 50

Then, divide both sides by -25. Then that leaves the answer.. p = -2

5 0
2 years ago
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