<span>Let the major axis = 2a , and the minor axis = 2b
∴ a = 26/2 = 13 and b = 24/2 = 12
and the equation of foci:
c² = a² - b²
= 13² - 12² = 169 - 144 = 25
∴ c = √25 = 5
∴ The distance between the foci = 2 * 5 = 10
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Answer:
A graph that has an axis of symmetry at x = 3 would be x^2 -6x + 12
Step-by-step explanation:
In order to find a graph that has an axis of symmetry at 3, use the equation for the axis of symmetry of a quadratic.
x = -b/2a
In this equation, a is the coefficient of x^2 and b is the coefficient of x. So, if we use 3 as x and we choose a random number to be a (1), we can solve for the b.
3 = -b/2(1)
3 = -b/2
6 = -b
b = -6
Now that we have this, we can put those two numbers as coefficients. The constant at the end can be anything.
Answer:
G. 7
Explanation:
The longest side must be less than the sum of the two shorter sides.
The difference between the longest and shortest sides must be less than the middle side.
l+a = 11
l < (a + 4) ... l < (11 - l + 4)
... 2 l < 15 ... l < 7.5
--Variables
l = 7 (Longest Side/Answer)
a = 4 (Other Missing Length)
m = 4 (Side Given)
This is how the calculation is done
1/2 = 24/x
x = 48
