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Alenkasestr [34]
2 years ago
5

A parallelogram has sides of length 16 units and 10 units. The shorter diagonal is 11 units. Find the measure of the longer diag

onal. Round to 2 decimal places, if necessary.
Mathematics
1 answer:
lord [1]2 years ago
4 0

The measure of the longer diagonal is 24.31 units

<h3>How to determine the longer diagonal?</h3>

The side lengths are given as;

a = 16

b = 10

The shorter diagonal is represented as d1, and it is given as

d1 = 11

The longer diagonal is represented as d2, and it is calculated using

d1^2 + d2^2 = 2 * (a^2 + b^2)

Substitute the known values in the above equation

11^2 + d2^2 = 2 * (16^2 + 10^2)

Evaluate the sum

121 + d2^2 =2 * 356

Evaluate the product

121 + d2^2 = 712

Subtract 121 from both sides

d2^2 = 591

Take the square root of both sides

d2 = 24.31

Hence, the measure of the longer diagonal is 24.31 units

Read more about parallelograms at:

brainly.com/question/970600

#SPJ1

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In this item, it is unfortunate that a figure, drawing, or illustration is not given. To be able to answer this, it is assumed that these segments are collinear. Points L, M, and N are collinear, and that L lies between MN. 

The length of the whole segment MN is the sum of the length of the subsegments, LN and LM. This can be mathematically expressed,
             LN + LM = MN

We are given with the lengths of the smalller segments and substituting the known values,
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<em>ANSWER: MN = 85</em>
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Answer:

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