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Alenkasestr [34]
2 years ago
5

A parallelogram has sides of length 16 units and 10 units. The shorter diagonal is 11 units. Find the measure of the longer diag

onal. Round to 2 decimal places, if necessary.
Mathematics
1 answer:
lord [1]2 years ago
4 0

The measure of the longer diagonal is 24.31 units

<h3>How to determine the longer diagonal?</h3>

The side lengths are given as;

a = 16

b = 10

The shorter diagonal is represented as d1, and it is given as

d1 = 11

The longer diagonal is represented as d2, and it is calculated using

d1^2 + d2^2 = 2 * (a^2 + b^2)

Substitute the known values in the above equation

11^2 + d2^2 = 2 * (16^2 + 10^2)

Evaluate the sum

121 + d2^2 =2 * 356

Evaluate the product

121 + d2^2 = 712

Subtract 121 from both sides

d2^2 = 591

Take the square root of both sides

d2 = 24.31

Hence, the measure of the longer diagonal is 24.31 units

Read more about parallelograms at:

brainly.com/question/970600

#SPJ1

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What is the value of x?
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Find the surface area of each figure. Round your answers to the nearest hundredth, if<br> necessary.
steposvetlana [31]

Answer:

1) 651.5 cm²

2) 462 cm²

3) 99 ft²

4) 1540.8 yd²

Step-by-step explanation:

1) Area of the trapezoid: (12 + 7)/2 * 6.5 = 61.75 cm²

Area of the lateral rectangles: 7*16 = 112 cm²

Area of the top rectangle: 12*16 = 192 cm²

Area of the bottom rectangle: 7*16 = 112 cm²

Area of the figure: 192 + 112 + 2*61.75 + 2*112 = 651.5 cm²

2) Area of the top and bottom squares: 11*11 = 121 cm²

Area of the lateral rectangles: 11*5 = 55 cm²

Area of the figure: 4*55 + 2*121 = 462 cm²

3)  Area of the trapezoid: (3 + 7)/2 * 3.5 = 17.5 ft²

Area of the lateral rectangles: 4*4 = 16 ft²

Area of the top rectangle: 7*4 = 28 ft²

Area of the bottom rectangle: 3*4 = 12 ft²

Area of the figure: 28 + 12 + 2*17.5 + 2*12 = 99 ft²

4) Area of the lateral rectangles: 11*12 = 132 yd²

Area of the top and bottom hexagons: 3*12*10.4 = 374.4 yd²

Area of the figure: 6*132 + 2*374.4 = 1540.8 yd²

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