Assume that the probability of a driver getting into an

Tarik rides a stationary bike and Janet rides her bike on a trail. Their data is shown

KiRa [710]

Answer:

Part a. The graph does not model a proportional relationship.

Part b. The values in table model a proportional relation.

3.5 minutes per mile.

Step-by-step explanation:

Part a.

The graph shown in the question representing Janet's data is not a straight line although it passes through the origin.

That is why the rate of change of distance with time is not constant.

Therefore, the graph does not model a proportional relationship.

Part b.

If we plot the data in the table using distance in miles along the y-axis and time in minutes along the x-axis, then we will get a straight line passing through the origin.

So, the values in the table model a proportional relation.

Now, Tarik's unit rate in minutes per miles will be $\frac{7-0}{2-0} =3.5$ minutes per mile. (Answer)

6 0

3 years ago

Which is the value of the expression (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed?

Flura [38]

Answer:

The value to the given expression is 8

Therefore $\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8$

Step-by-step explanation:

Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed

Given expression can be written as below

$\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3$

To find the value of the given expression:

$\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}$

( By using the property ( $(\frac{a}{b})^m=\frac{a^m}{b^m}$ )

$=\frac{(10^4)^3(5^2)^3}{(10^3)^3(5^3)^3}$

( By using the property $(ab)^m=a^mb^m$ )

$=\frac{(10^{12})(5^6)}{(10^9)(5^9)}$

( By using the property $(a^m)^n=a^{mn}$ )

$=(10^{12})(5^6)(10^{-9})(5^{-9})$

( By using the property $\frac{1}{a^m}=a^{-m}$ )

$=(10^{12-9})(5^{6-9})$ (By using the property $a^m.b^n=a^{m+n}$ )

$=(10^3)(5^{-3})$

$=\frac{10^3}{5^3}$ ( By using the property $a^{-m}=\frac{1}{a^m}$ )

$=\frac{1000}{125}$

$=8$

Therefore $\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8$

Therefore the value to the given expression is 8

3 0

2 years ago

Read 2 more answers

How do you do solve this?

solniwko [45]

The relative frequency is the frequency of the item divided by the total number of all items. The total number of all items here is: 50 + 40 + 90 +20 = 200.

$Burgers = \frac{50}{200} = 25%$
$Pasta = \frac{40}{200} = 20%$
$Pizza = \frac{90}{200} = 45%$
$Salad = \frac{20}{200} = 10%$

Hope this helps!

3 0

3 years ago

Help me i dont know what i am doing at all

nika2105 [10]

You are doing the distributive property.
68.5j+76.54

7 0

2 years ago

A dolphin in an aquarium is 12 feet long. A scale model of the dolphin is 3.5 inches long. What is the scale factor of the mode?

polet [3.4K]

Assuming the life sized dolphin is 12 ft long, what we want to know is what factor do you multiply 12 ft by to get 3.5 inches so converting this to an equation gives: 12*f=3.5 solving for f gives f=3.5/12=.29166...The units on the factor are inches/foot.

So to get the size if anything linear in the small scale you just multiply it's dimension in the full scale by f.

3 0

3 years ago