5 -2[3 + (5-1)* ÷ 2•5]
1 answer:
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Answer with explanation:
Average Height of tallest Building in San Francisco
Average Height of tallest Building in Los Angeles
→→Difference between Height of tallest Building in Los Angeles and Height of tallest Building in San Francisco
=233.9-197.8
=36.1
⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.
⇒Part B
Mean absolute deviation for the 10 tallest buildings in San Francisco
|260-197.8|=62.2
|237-197.8|=39.2
|212-197.8|=14.2
|197 -197.8|= 0.8
|184 -197.8|=13.8
|183-197.8|=14.8
|183-197.8|= 14.8
|175-197.8|=22.8
|174-197.8|=23.8
|173 -197.8|=24.8
Average of these numbers
Mean absolute deviation=23.12
Given parameters:
Length of the gift box = 8 inches
Width of the box = 3 inches
Height of the box = 4 inches
Unknown :
Length of its longest diagonal = ?
Solution:
This is a rectangular box.
To find the diagonal of such box, let us use the formula below;
Diagonal =
l is the length
w is the width
h is the height
Input the parameters and solve;
Diagonal = = 9.4inches
The diagonal of the box is 9.4inches