Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day.
Answer:
b=15 g=25
Step-by-step explanation:
lets translate that story problem to mathematics equations
the problem told that no. of girls are 10 more than no of boys so this will =
g=b+10
then in class there are 40 students that means
g+b=40
now we have to equations with two variables then we should substitute
(b+10)+b=40
lets remove the brackets
2b+10=40 subtract 10 from both sides
2b=30 now divide both by 2
b=15 so g=25 after you write the equation once again with the new proof or number
Answer:
Number of 8th Graders = 360 - X
Step-by-step explanation:
As you can see this question is not complete and lacks the essential data. But we will try to create a mathematical expression to calculate the number of students on the A honor roll which are from 8th grade.
As we know:
Total number of students on the A honor roll = 360
We are asked to calculate, number of students from 8th grade on the A honor roll.
So, let's assume that "X" represents the all the students who are on the A honor roll except 8th grade.
Mathematical Expression:
Number of 8th Graders = Total number of students on the A honor roll - X
Number of 8th Graders = 360 - X
So, if you know the value of X, you can easily calculate the number of students which are from 8th grade on the A honor roll.
Answer:
C is the answer
Step-by-step explanation:
2π/2 = π
