If the remaining 4 letters can be anything, you have 2*26^4 = 913,952 possible 5-letter ham radio call signs.
Answer:
COMPLETE QUESTION:
To the right are drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?
a)To the 7 1/2 mark b)To the 9th mark c)To the 8th mark d)To the 7 1/3 mark
e)To the 11th mark
ANSWER : Option D (To the 7 1/3 mark)
Step-by-step explanation:
First part of the question enables us to get the relationship between the radius of the wider cylinder (R) and the narrow cylinder(r) i.e
Volume of cylinders
π x R² x 4 = πxr²x 6
R²/r² = 6/4
after both cylinder were emptied
π x R² x h = π x r² x 11
R²/r² = 6/4 = 11/h
h = (4 x 11) /6 = 22/3 = 7 1/3 mark
Therefore, the height of the water in the wide cylinder is 7 1/3
Answer:
question 1 is actually 82/100 is equivalent to 41/50
question 2 is 5/10 or 50/100
and question 3 is 17/100
(pls mark brainliest)
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Answer is b hope it helps
