To solve for x:
Move all the terms containing "x" to the left side of the equation. Do this by adding x to both sides.
2x+x=3x. The new equation is:
3x-1/2=3
Now, move all terms not containing "x" to the right side of the equation. Do this by adding 1/2 to both sides.
3x=3+1/2 The new equation is:
3x=3 1/2, or 3.5
The final step is to isolate x. To do so, divide each side by 3.
3x/3 = 3 1/2 /3 The new equation is:
x=1 1/6
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
I hope this helps you
Volume = pi.r^2.h
36= pi.r^2.h
Volume =pi.r^2.3/4h
Volume =pi.r^2.h.3/4
Volume =36.3/4
Volume =9.3
Volume =27
Answer:4.08 ft a year or 1 and 5/8 feet a year (approx)
Step-by-step explanation:
It's 12.5 feet the first year
51 feet 5 years later
If you do the math and divide 51 by 12.5, you get 4.08 which is around 1 and 5/8 ft
12.5x4.08 is 51 feet.
So the tree grows approximately 1 and 5/8 feet a year