Help with Trigonometric identities

Mathematics

1 answer:

Gre4nikov [31]2 years ago

3 0

Answer:

Option 2

Step-by-step explanation:

Since theta is in the third quadrant, the sine of theta is negative.

By the Pythagorean identity,

$\sin \theta=-\frac{\sqrt{105}}{13}$

So, using the double angle formula for sine, we get that

$\sin 2\theta=\frac{16\sqrt{105}}{169}$

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