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Xelga [282]
2 years ago
15

4. Ashley claims that if she triples the side length of a square (s), the area of the square will also be tripled. Do you agree?

Explain your thinking. ​
Mathematics
1 answer:
stepladder [879]2 years ago
5 0

<u>Answer</u><u> </u><u>:</u><u>-</u>

Let the side of the square measure a cm, thus, according to the question,

  • New length = 3(a cm)

We know that,

➭ Area ( Square ) = a²

Thus, the area of the square with normal length i.e. a cm, will be,

⤳ Area = a x a

⤳ Area = a²

Now, by taking the new length, the area will become,

⤳Area = 3a x 3a

⤳ Area = 9a²

Now,

We observe that, if we divide these, we get,

➤ 9a²/a²

( a² will get canceled since its common )

Thus, the ratio becomes,

➭ 9 : 1 = Area square with tripled length : Area of square

Thus, the area will increase by 9 times, and not 3.

Hence, Ashley's assumptions are wrong.

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12a^2*b^4-36a^2*b+44abc
spayn [35]

Let's simplify step-by-step.

12a^2*b^4-36a^2*b+44abc=

There are no like terms.

Answer:

12a^2*b^4-36a^2*b+44abc=

5 0
2 years ago
Please please help with this. i need all 10 plsss. will mark as brainliest
iren2701 [21]

Answer:

1) (x+3)(x+4)

2) (x-9)(x+1)

3) (x-6)(x+5)

4) (x-3)(x-5)

5) (x-10)(x+1)

6) (x+3)(x+8)

7) (x-2)(x-8)

8) (x+4)(x-1)

9) (x-9)(x+5)

10) (x-8)(x+2)

5 0
3 years ago
Please help i am giving away brainiliest
Ede4ka [16]

Answer: b is the answer

Step-by-step explanation: have a nice day

3 0
2 years ago
In a box of marbles, the ratio of red marbles to total marbles is 2:5. the ratio of green marbles to total marbles is 3:10. if t
STALIN [3.7K]
Ratio:

Red : Total 
  2   :    5
 (x2)    (x2)
  4   :   10

Green : Total
  3   :       10

Total of red and green marbles = 4 + 3 = 7

Blue marbles = 10 - 7 = 3

10 parts = 40 marbles
1 part = 40 ÷ 10 = 4
3 parts = 4 x 3 = 12

Answer: There are 12 blue marbles.
7 0
2 years ago
Identify the slope and y-intercept of each of the following lines. Then graph each line.
viktelen [127]

First <u>rewrite the equation</u> in slope intercept form

slope intercept form: y = mx + b [ where m is slope and b is y-intercept ]

\rightarrow \sf 8y = -2x+32

\rightarrow \sf y =\dfrac{ -2x+32}{ 8}

\rightarrow \sf y =\dfrac{ -2x}{ 8} + \dfrac{32}{8}

\rightarrow \sf y =\dfrac{ -1}{ 4}x + 4

<u>comparing</u> with y = mx + b

  • slope: -1/4     and   y-intercept: 4

x-intercept:          ( then y will be 0 )

\hookrightarrow  \sf -2x + 32 = 0

\hookrightarrow  \sf -2x  = -32

\hookrightarrow  \sf x  = 16

In order to graph the line

  • plot x = 16 on the x-axis     coordinate: (16, 0)
  • plot y = 4 on the y-axis     coordinate: (0, 4)
  • Then using a scale/ruler draw a straight line through this points.

Graph:

8 0
2 years ago
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