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Xelga [282]
2 years ago
15

4. Ashley claims that if she triples the side length of a square (s), the area of the square will also be tripled. Do you agree?

Explain your thinking. ​
Mathematics
1 answer:
stepladder [879]2 years ago
5 0

<u>Answer</u><u> </u><u>:</u><u>-</u>

Let the side of the square measure a cm, thus, according to the question,

  • New length = 3(a cm)

We know that,

➭ Area ( Square ) = a²

Thus, the area of the square with normal length i.e. a cm, will be,

⤳ Area = a x a

⤳ Area = a²

Now, by taking the new length, the area will become,

⤳Area = 3a x 3a

⤳ Area = 9a²

Now,

We observe that, if we divide these, we get,

➤ 9a²/a²

( a² will get canceled since its common )

Thus, the ratio becomes,

➭ 9 : 1 = Area square with tripled length : Area of square

Thus, the area will increase by 9 times, and not 3.

Hence, Ashley's assumptions are wrong.

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Answer:

(e) (27, 2) and (243, 18)

(g) (63, 9) and (84, 12)

(d) (45, 15) and (60, 20)

(c) (27, 12) and (72, 32)

(a) (15, 30) and (20, 40)

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Step-by-step explanation:

Required

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Slope (m) is calculated using:

m = \frac{y_2 -y_1}{x_2 - x_1}

So, we have:

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m = \frac{40 -30}{20- 15}

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m = 0.44

(d) (45, 15) and (60, 20)

m = \frac{20-15}{60- 45}

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(f) (18, 63) and (24, 84)

m = \frac{84-63}{24- 18}

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(g) (63, 9) and (84, 12)

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(g) (63, 9) and (84, 12)

(d) (45, 15) and (60, 20)

(c) (27, 12) and (72, 32)

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(b) (12, 32) and (18, 48)

(f) (18, 63) and (24, 84)

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