Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
Answer:
Step-by-step explanation:
9n-2
Answer:
1 answer which would be -5+5 which =0
Step-by-step explanation:
<u>Answer-</u>
<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>
<u>Solution-</u>
The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.
We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.
We know that, the conditional probability of occurrence of A given that B occurs is,
Putting these values,
The negitives are far from the 0 so its less than the non negitives