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3 years ago

Write in standard form. a) 2 4 b) 10 3 c) 3 5 d) 7 3 e) 2 8 f) 4 1 PLZ HELP!!!!!

Mathematics

1 answer:

Rama09 [41]3 years ago

4 0

A) 24

24 x 10

b)

103

103 x 10

C) 35

35 x 10

D) 73

73 x 10

E) 28

28 x 10

F) 41

41 x 10

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1) 3r² – 2r=-9<br> Quadratic formula

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Solving the equation $3r^2-2r=-9$ using quadratic formula we get: $\mathbf{ r=\frac{1+\sqrt{26}\:i}{3}\:or\: r=\frac{1-\sqrt{26}\:i}{3}}$

Step-by-step explanation:

We need to solve the equation $3r^2-2r=-9$ using quadratic formula.

The quadratic formula is: $r=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

For the given equation: $3r^2-2r=-9$

We can write it as: $3r^2-2r+9=0$

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$r=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\r=\frac{-(-2)\pm\sqrt{(-2)^2-4(3)(9)}}{2(3)}\\r=\frac{2\pm\sqrt{4-108}}{6}\\r=\frac{2\pm\sqrt{-104}}{6}\\We\:know\:that: \sqrt{-1}=i\\ r=\frac{2\pm\sqrt{26} \:i}{6}\\ r=\frac{2+2\sqrt{26}\:i}{6}\:or\: r=\frac{2-2\sqrt{26}\:i}{6}\\ r=\frac{2(1+\sqrt{26}\:i)}{6}\:or\: r=\frac{2(1-\sqrt{26}\:i)}{6}\\ r=\frac{1+\sqrt{26}\:i}{3}\:or\: r=\frac{1-\sqrt{26}\:i}{3}$

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