A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the class passed both exams. What p
ercent of those who passed the second exam also passed the first exam?
2 answers:
This is an example of conditional probability because we are trying to find the probability of an event occurring GIVEN the occurrence of some other event. There is a formula for this (see image attached).
If we follow this formula, the numerator would be the probability of (A AND B) which in this case is "48% of the class passed BOTH exams." The denominator in the formula would be that "60% of the class passed ONLY THE SECOND exam."
Therefore, P(A and B) = 0.48, which is 48% expressed as a decimal and P(B)= 0.60, which is 60% expressed as a decimal. Then, you can figure out the answer by dividing.
If we follow this formula, the numerator would be the probability of (A AND B) which in this case is "48% of the class passed BOTH exams." The denominator in the formula would be that "60% of the class passed ONLY THE SECOND exam."
Therefore, P(A and B) = 0.48, which is 48% expressed as a decimal and P(B)= 0.60, which is 60% expressed as a decimal. Then, you can figure out the answer by dividing.
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<h2>Hello!</h2>
The answer is:
The correct option is
a)
Since a right triangle is formed, we can calculate the resultant force using the Pythagorean Theorem which states that:
Where,
c, is the hypothenuse.
a, is one triangle leg.
b, is the other triangle leg.
So, we are given the information:
So, calculating the resultant force (hypothenuse), we have:
Hence, the expression that would find the result velocity is:
a) [tex]Resultant=\sqrt{22^{2} +4^{2} }[/tex]
Have a nice day!