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2 years ago

What's the answer and how do I even do this

Mathematics

2 answers:

kkurt [141]2 years ago

6 0

Answer: -1

Step-by-step explanation:

bulgar [2K]2 years ago

3 0

Answer:

Step-by-step explanation:

<u><em>See attached image</em></u>

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Simple equation IS ALSO KNOWN HAS

antoniya [11.8K]

Answer:

linear equation.

Step-by-step explanation:

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3 years ago

Rhianna and Myra, both teachers, are adding books to their class libraries. Rhianna's classroom started out with a collection of

Hunter-Best [27]

Answer:

21 books; 5 weeks

Step-by-step explanation:

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2 years ago

Which of the following possibilities will form a triangle?

zhenek [66]

D will form a triangle

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4 0

3 years ago

Read 2 more answers

Wazma bought some new pants, but the 34 inch inseam was too long. If he wants the inseam to be 3013 inches long, how much length

KiRa [710]

The length of the inseam to be removed from the pant is 3 2 / 3 inches.

<h3 /><h3>How to find the length to be removed?</h3>

The length of the pant he bought is 34 inches and it was too long.

He wants the length to be 30 1 / 3 inches long.

Therefore, the amount of length to be removed can be calculated as follows;

34 - 30 1 / 3

$30\frac{1}{3} = \frac{91}{3}$

Hence,

$34-\frac{91}{3}=\frac{102-91}{3} =\frac{11}{3}=3\frac{2}{3} inches$

Therefore, the number to be removed is 3 2 / 3 inches

learn more on length here: brainly.com/question/11427600

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7 0

2 years ago

Factor the polynomial function over the complex numbers. f(x)=x^4-x^3-2x−4 Enter your answer in the box. f(x) = The answer is: (

Vladimir79 [104]

Answer:

Factors: $(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

Step-by-step explanation:

We are given a polynomial:

$f(x)=x^4-x^3-2x-4$

We have to factor the given polynomial into its complex factors.

The factorization can be done as follows:

$f(x)=x^4-x^3-2x-4 = 0\\x^4-x^3-2x-4 = 0\\x^4-4-x^3-2x=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^4-4)-(x^3+2x) = 0\\(x^2+2)(x^2-2)-x(x^2+2) = 0\\(x^2+2)(x^2-2-x) = 0\\(x^2+2)(x^2-x-2) = 0\\(x^2+2)(x^2-2x-+x-2) = 0\\(x^2+2)((x(x-2)+1(x-2))=0\\(x^2+2)(x+1)(x-2)=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^2-(\sqrt{-2})^2)(x+1)(x-2)=0\\(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

8 0

2 years ago