Answer:
option B. 
Step-by-step explanation:
we know that
1) The two diagonals of a rhombus are perpendicular
2) The sum of the interior angles in any triangle must be equal to 180 degrees
Let
O ----> the intersection point of the diagonals of the rhombus
In the right triangle OAD
solve for x
The way you say this is one hundred nineteen ten thousandths if this helps mark brainiest
The inequality 
gives the least number of buses, b, needed for the trip. The least number of buses is 9
<u>Solution:</u>
Given that, There are 412 students and 20 teachers taking buses on a trip to a museum.
Each bus can seat a maximum of 48.
We have to find which inequality gives the least number of buses, b, needed for the trip?
Now, there are 412 students and 20 teachers, so in total there are 412 + 20 = 432 travelers
<em><u>The number of buses required “b” is given as:</u></em>
Number of buses required ≥ 9 buses.
But least number will be 9 from the above inequality.
Hence, the inequality 
gives least count of busses and least count is 9.
In this item, it is unfortunate that a figure, drawing, or illustration is not given. To be able to answer this, it is assumed that these segments are collinear. Points L, M, and N are collinear, and that L lies between MN.
The length of the whole segment MN is the sum of the length of the subsegments, LN and LM. This can be mathematically expressed,
LN + LM = MN
We are given with the lengths of the smalller segments and substituting the known values,
MN = 54 + 31
MN = 85
<em>ANSWER: MN = 85</em>
-4.75= z/2
Multiply both sides by 2
-4.75(2)= z/2(2)
Cross out 2 and 2, divide by 1 and becomes z
z=-9.5
Answer: z= -9.5
