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LenaWriter [7]
3 years ago
9

Trapezoid ABCD is rotated 90° clockwise. What rule shows the input and output of the reflection, and what is the new coordinate

of A′?
(x, y) → (−x, −y); A′ is at (5, −1)
(x, y) → (−y, x); A′ is at (−1, −5)
(x, y) → ( y, −x); A′ is at (1, 5)
(x, y) → (x, −y); A′ is at (−5, −1)
Mathematics
2 answers:
Rina8888 [55]3 years ago
8 0
The answer is B (-y,x)
ExtremeBDS [4]3 years ago
3 0

Answer:

C.

Step-by-step explanation:

The first coordinate is (-5,1) so then (y,-x) and (1,5). bam boom pow

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If f(x)=x^2 and g(x)=1÷2x+3 find g(f(-1))
gogolik [260]

ANSWER

g(f( - 1)) = \frac{1}{5 }

EXPLANATION

The given function is:

f(x) =  {x}^{2}

and

g(x) =  \frac{1}{2x + 3}

g(f(x)) = g( {x}^{2} )

g(f(x)) = \frac{1}{2{x}^{2} + 3 }

To find g(f(-1)), we substitute x=-1, to obtain;

g(f( - 1)) = \frac{1}{2{( - 1)}^{2} + 3 }

We simplify the square in the denominator to get,

g(f( - 1)) = \frac{1}{2+ 3 }

We now add the denominator to obtain;

g(f( - 1)) = \frac{1}{5 }

6 0
3 years ago
x= 1, 2, 3, 4, 5. y=11\4, 25\4, 39\4, 53\4, 67\4. what equation relates y to x in the values x and y?
larisa86 [58]
(1,11/4)(2,25/4)
slope = (25/4 - 11/4) / (2 - 1) = (14/4) / 1 = 14/4 = 7/2

y = mx + b
slope(m) = 7/2
(1,11/4)...x = 1 and y = 11/4
now we sub and find b, the y int
11/4 = 7/2(1) + b
11/4 = 7/2 + b
11/4 - 7/2 = b
11/4 - 14/4 = b
-3/4 = b

so ur equation is : y = 7/2x - 3/4
4 0
3 years ago
Find the point, M, that divides segment AB into a ratio of 5:5 if A is at (0, 15) and B is at (20, 0).
Airida [17]

C

a ratio of 5 : 5 simplifies to 1 : 1, which basically means we require the midpoint of the line segment

using the midpoint formula

M = [\frac{1}{2} (0 + 20 ), \frac{1}{2} (15 + 0)] = (10, 7.5 )


5 0
3 years ago
Read 2 more answers
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