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Romashka-Z-Leto [24]
2 years ago
13

Pls helpp

Mathematics
1 answer:
irina1246 [14]2 years ago
7 0
  • you will need 2 busses to only transport the boys.
  • Mark is at (1 + 5/6) miles of his house.
<h3>How many buses would it take to carry only the boys?</h3>

We know that there are (3 + 1/2) groups, such that each group fill one bus.

2/5 of the students are boys, then the number of groups that we can make only with boys is:

(2/5)*(3 + 1/2) = 6/5 + 1/5 = 7/5 = 5/5 + 2/5 = 1 + 2/5

Then you can make one and a little less than a half of a group, which means that you need 1 and 2/5 of a buss to transport the boys, rounding that to the a whole number, you will need 2 busses to only transport the boys.

<h3>How far is Mark from his house?</h3>

The original distance is:

D = (2 + 3/4) miles.

But Mark only covers 2/3 of that distance, then we have:

d = (2/3)*D = (2/3)*(2 + 3/4) miles = (4/3 + 2/4) miles

d = (4/3 + 1/2) miles = (8/6 + 3/6) miles = (1 + 5/6) miles

Mark is at (1 + 5/6) miles of his house.

If you want to learn more about mixed numbers:

brainly.com/question/21610929

#SPJ1

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0 (zero)

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Solve the inequality −8 ≤ z + 6.4
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5 0
3 years ago
Need help, please <br><br>asap
igomit [66]

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When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)

Thus there are 11 total possible outcomes.

Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)

This means there are 7 outcomes with sum greater than or equal to 9. 

Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11

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