Answer:
The code will produce:-
2.4
Explanation:
In this code the result of the arithmetic operation is stored in the variable c.On evaluating the expression it divides 12.0 by 5 which results in 2.4 and it is stored in float variable c.Then it is printed on the screen using print statement.Since the c is double variable so the result will be a decimal number.
Hence the answer is 4.
Answer:
Pre-processors look at organize traffic and screens parcel transmissions by examining andreassembling divided data.Frag2:preprocessor that battles against IP fracture attacks.Attackers sends a fragmentedTCP bundle with header data that gets entrance through a firewall.At the equivalent time,other parcels with vindictive information "slip" by the firewall undetected because of the fragmentationbeing so little by overwriting the header information.The frag2 pre-processor is specificallydesigned to break down bundle discontinuity to search out noxious information in the sections, which iswhy this pre-processor ought to never be turned off.Stream4:preprocessor Snort uses to coordinate assault marks over numerous packets.Anattacker endeavors to send different parcels into the system conveying parts of the attackpayload which are required to be reassembled by the host so as to start an attack.Stream4 stores the bits of the mark until all bundles are transmitted.Once they are alltransmitted, Stream4 finishes the signature and an alarm is created.
Explanation:
Well if your talking about physically you could get some compressed air and blow it out. Or if your talking about performance you could try to re-install the os you have on it or replace the hdd with a ssd or higher performance hard disk for it to run like new. :)
Answer:
Check the explanation
Explanation:
#!usr/bin/python
#FileName: sieve_once_again.py
#Python Version: 2.6.2
#Author: Rahul Raj
#Sat May 15 11:41:21 2010 IST
fi=0 #flag index for scaling with big numbers..
n=input('Prime Number(>2) Upto:')
s=range(3,n,2)
def next_non_zero():
"To find the first non zero element of the list s"
global fi,s
while True:
if s[fi]:return s[fi]
fi+=1
def sieve():
primelist=[2]
limit=(s[-1]-3)/2
largest=s[-1]
while True:
m=next_non_zero()
fi=s.index(m)
if m**2>largest:
primelist+=[prime for prime in s if prime] #appending rest of the non zero numbers
break
ind=(m*(m-1)/2)+s.index(m)
primelist.append(m)
while ind<=limit:
s[ind]=0
ind+=m
s[s.index(m)]=0
#print primelist
print 'Number of Primes upto %d: %d'%(n,len(primelist))
if __name__=='__main__':
sieve()
