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1 year ago

Ammonium carbonate decomposes upon heating according to

Chemistry

1 answer:

BaLLatris [955]1 year ago

7 0

The total volume of the gas produced, given the data from the question is 11.84 L

<h3>How to determine the mole of (NH₄)₂CO₃</h3>

Mass of (NH₄)₂CO₃ = 11.83 g
Molar mass of (NH₄)₂CO₃ = 96 g/mol
Mole of (NH₄)₂CO₃ =?

Mole = mass / molar mass

Mole of (NH₄)₂CO₃ = 11.83 / 96

Mole of (NH₄)₂CO₃ = 0.123 mole

<h3>How to determine the volume of NH₃</h3>

Balanced equation

(NH₄)₂CO₃ -> 2NH₃(g) + CO₂(g) + H₂O(g)

From the balanced equation above,

1 mole of (NH₄)₂CO₃ decomposed to produce 2 moles of NH₃

Therefore,

0.123 mole of (NH₄)₂CO₃ will decompose to produce = 0.123 × 2 = 0.246 mole of NH₃

Thus, we can determine the volume of NH₃ produced by using the ideal gas equation as follow:

Temperature (T) = 22 °C = 22 + 273 = 295 K
Pressure (P) = 1.02 bar
Gas constant (R) = 0.08314 bar.L/Kmol
Number of mole (n) = 0.246 moles
Volume of NH₃ (V) =?

PV = nRT

Divide both side by P

V = nRT / P

V = (0.246 × 0.08314 × 295) / 1.02

Volume of NH₃ = 5.92 L

<h3>How to determine the volume of CO₂</h3>

Balanced equation

(NH₄)₂CO₃ -> 2NH₃(g) + CO₂(g) + H₂O(g)

From the balanced equation above,

1 mole of (NH₄)₂CO₃ decomposed to produce 1 moles of CO₂

Therefore,

0.123 mole of (NH₄)₂CO₃ will also decompose to produce = 0.123 mole of CO₂

Thus, we can determine the volume of CO₂ produced by using the ideal gas equation as follow:

Temperature (T) = 22 °C = 22 + 273 = 295 K
Pressure (P) = 1.02 bar
Gas constant (R) = 0.08314 bar.L/Kmol
Number of mole (n) = 0.123 moles
Volume of CO₂ (V) =?

PV = nRT

Divide both side by P

V = nRT / P

V = (0.123 × 0.08314 × 295) / 1.02

Volume of CO₂ = 2.96 L

<h3>How to determine the volume of H₂O</h3>

Balanced equation

(NH₄)₂CO₃ -> 2NH₃(g) + CO₂(g) + H₂O(g)

From the balanced equation above,

1 mole of (NH₄)₂CO₃ decomposed to produce 1 moles of H₂O

Therefore,

0.123 mole of (NH₄)₂CO₃ will also decompose to produce = 0.123 mole of H₂O

Thus, we can determine the volume of H₂O produced by using the ideal gas equation as follow:

Temperature (T) = 22 °C = 22 + 273 = 295 K
Pressure (P) = 1.02 bar
Gas constant (R) = 0.08314 bar.L/Kmol
Number of mole (n) = 0.123 moles
Volume of H₂O (V) =?

PV = nRT

Divide both side by P

V = nRT / P

V = (0.123 × 0.08314 × 295) / 1.02

Volume of H₂O = 2.96 L

<h3>How to determine the total volume of gas produced</h3>

Volume of NH₃ = 5.92 L
Volume of CO₂ = 2.96 L
Volume of H₂O = 2.96 L
Total volume of gas =?

Total volume = 5.92 + 2.96 + 2.96

Total volume of gas = 11.84 L

Learn more about ideal gas equation:

brainly.com/question/4147359

Learn more about stoichiometry:

brainly.com/question/14735801

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<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 Bi + 3 Cl₂ → 2 BiCl₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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Cl₂: 3 moles
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Cl₂: 70.90 g/mole
BiCl₃: 315.45 g/mole

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<h3>Mass of Cl₂ required</h3>

The following rule of three can be applied: If by reaction stoichiometry 630.9 grams of BiCl₃ are formed by 212.7 grams of Cl₂, 3.32 grams of BiCl₃ are formed by how much mass of Cl₂?

$mass of Cl_{2} =\frac{3.32 grams of BiCl_{3}x212.7 grams of Cl_{2} }{630.9 grams of BiCl_{3}}$

<u><em>mass of Cl₂= 1.119 grams</em></u>

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