The total volume of the gas produced, given the data from the question is 11.84 L
<h3>How to determine the mole of (NH₄)₂CO₃</h3>
- Mass of (NH₄)₂CO₃ = 11.83 g
- Molar mass of (NH₄)₂CO₃ = 96 g/mol
- Mole of (NH₄)₂CO₃ =?
Mole = mass / molar mass
Mole of (NH₄)₂CO₃ = 11.83 / 96
Mole of (NH₄)₂CO₃ = 0.123 mole
<h3>How to determine the volume of NH₃</h3>
Balanced equation
(NH₄)₂CO₃ -> 2NH₃(g) + CO₂(g) + H₂O(g)
From the balanced equation above,
1 mole of (NH₄)₂CO₃ decomposed to produce 2 moles of NH₃
Therefore,
0.123 mole of (NH₄)₂CO₃ will decompose to produce = 0.123 × 2 = 0.246 mole of NH₃
Thus, we can determine the volume of NH₃ produced by using the ideal gas equation as follow:
- Temperature (T) = 22 °C = 22 + 273 = 295 K
- Pressure (P) = 1.02 bar
- Gas constant (R) = 0.08314 bar.L/Kmol
- Number of mole (n) = 0.246 moles
- Volume of NH₃ (V) =?
PV = nRT
Divide both side by P
V = nRT / P
V = (0.246 × 0.08314 × 295) / 1.02
Volume of NH₃ = 5.92 L
<h3>How to determine the volume of CO₂</h3>
Balanced equation
(NH₄)₂CO₃ -> 2NH₃(g) + CO₂(g) + H₂O(g)
From the balanced equation above,
1 mole of (NH₄)₂CO₃ decomposed to produce 1 moles of CO₂
Therefore,
0.123 mole of (NH₄)₂CO₃ will also decompose to produce = 0.123 mole of CO₂
Thus, we can determine the volume of CO₂ produced by using the ideal gas equation as follow:
- Temperature (T) = 22 °C = 22 + 273 = 295 K
- Pressure (P) = 1.02 bar
- Gas constant (R) = 0.08314 bar.L/Kmol
- Number of mole (n) = 0.123 moles
- Volume of CO₂ (V) =?
PV = nRT
Divide both side by P
V = nRT / P
V = (0.123 × 0.08314 × 295) / 1.02
Volume of CO₂ = 2.96 L
<h3>How to determine the volume of H₂O</h3>
Balanced equation
(NH₄)₂CO₃ -> 2NH₃(g) + CO₂(g) + H₂O(g)
From the balanced equation above,
1 mole of (NH₄)₂CO₃ decomposed to produce 1 moles of H₂O
Therefore,
0.123 mole of (NH₄)₂CO₃ will also decompose to produce = 0.123 mole of H₂O
Thus, we can determine the volume of H₂O produced by using the ideal gas equation as follow:
- Temperature (T) = 22 °C = 22 + 273 = 295 K
- Pressure (P) = 1.02 bar
- Gas constant (R) = 0.08314 bar.L/Kmol
- Number of mole (n) = 0.123 moles
- Volume of H₂O (V) =?
PV = nRT
Divide both side by P
V = nRT / P
V = (0.123 × 0.08314 × 295) / 1.02
Volume of H₂O = 2.96 L
<h3>How to determine the total volume of gas produced</h3>
- Volume of NH₃ = 5.92 L
- Volume of CO₂ = 2.96 L
- Volume of H₂O = 2.96 L
- Total volume of gas =?
Total volume = 5.92 + 2.96 + 2.96
Total volume of gas = 11.84 L
Learn more about ideal gas equation:
brainly.com/question/4147359
Learn more about stoichiometry:
brainly.com/question/14735801
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