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DochEvi [55]
2 years ago
9

Identify the following as an element or compound copper II oxide

Chemistry
2 answers:
liberstina [14]2 years ago
7 0
Copper II oxide is a compound
user100 [1]2 years ago
4 0
Copper II oxide is a compound.
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Which law of thermodynamics states that the entropy
Arte-miy333 [17]

Answer:second law of thermodynamics

Explanation:the second law of thermodynamics states that the total entropy of an isolated system can never decrease over time and is constant if only if all processes are reversible.

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3 years ago
Which of these is not a biomass source?
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A biomass source is an natural material.

The sun is natural.

Manure is natural.

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Amylose is a form of starch which has ________. only β-1,4-bonds between glucose units only α-1,4-links bonds glucose units hemi
forsale [732]

Answer: Amylose is a form of starch which has only α-1,4-links bonds glucose units.

Explanation:

Amylose is a polysaccharide made up of α(1-4) bound glucose molecules. The carbon atoms on glucose are numbered, starting at the aldehyde (C=O) carbon, so, in amylose, the 1-carbon on one glucose molecule is linked to the 4-carbon on the next glucose molecule.

5 0
3 years ago
How many moles are present in
olasank [31]

Answer: (a) There are 0.428 moles present in 12 g of N_{2} molecule.

(b) There are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

Explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of N_{2} is 28 g/mol so its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol

So, there are 0.428 moles present in 12 g of N_{2} molecule.

(b). According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

Therefore, moles present in 12.044 \times 10^{23} particles are calculated as follows.

Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol

So, there are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

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