The structure of ozone most closely resembles 1. , a linear molecule with different lengths of chemical bonds. 2. , a bent molec
ule with the same length of chemical bonds. 3. , a linear molecule with the same length of chemical bonds. 4. , a bent molecule with different lengths of chemical bonds.
1 answer:
Answer:
A bent molecule with the same length of chemical bonds
Explanation:
Ozone has three 3 oxygen atoms and its molecular formula of ozone is .
The central oxygen atom is sp2 hybridized and has one lone pair. Because sp2 hybridization and lone pair, shape is bend. Resonance occur in ozone because lone pair and double bond are in conjugation, therefore, ozone can be represented as a resonance hybrid with same bond lengths.
Therefore, option 2 is correct.
A bent molecule with the same length of chemical bonds
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Answer:
The mass of hydrogen gas in the mixture: <u>w₂ = 0.433 g</u>
Explanation:
<u>According to the ideal gas equation: </u>
for an ideal gas,
and
Here, P: total pressure of the gases = 2.14 atm
V: total volume of the gases = 6.68 L
T: temperature = 19 °C = 19+273.15 = 292.15K (∵ 0°C = 273.15K)
R: gas constant = 0.08206 L·atm·K⁻¹·mol⁻¹
: total number of moles of gases
<u>To calculate the total number of moles of gases</u>:
= <u>0.5963 moles</u>
Let, the number of moles of carbon dioxide be n₁ and number of moles of hydrogen be n₂
<u>Given:</u> mass of carbon dioxide: w₁ = 16.8 g, mass of hydrogen: w₂ = ?g
molar mass of carbon dioxide: m₁ = 44.01 g/mol, molar mass of hydrogen: m₂= 2.016 g/mol
Therefore, = n_{1}+n_{2} = (w₁ ÷ m₁) + (w₂ ÷ m₂)
⇒ 0.5963 mol = (16.8 g ÷ 44.01 g/mol) + (w₂ ÷ 2.016 g/mol)
⇒ 0.5963 mol = (0.3817mol) + (w₂ ÷ 2.016 g/mol)
⇒ 0.5963 mol - 0.3817mol = (w₂ ÷ 2.016 g/mol)
⇒ 0.2146 mol = (w₂ ÷ 2.016 g/mol)
⇒ w₂ = 0.433 g
<u>Therefore, the mass of hydrogen gas in the mixture: w₂ = 0.433 g</u>