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3 years ago

A person's heartbeat is 73 beats per minute. If his heart beats 3.1e9 times in a lifetime, how long does the person live?

Chemistry

1 answer:

tiny-mole [99]3 years ago

7 0

Answer: The person lived for 80.66 years.

Explanation:

Heart beat of the person = 73 beat /min

Number of total heart beats = $3.1\times 10^{9}$

Life span of the person : $\frac{\text{Total heart beats of the person}}{\text{Heart beat per minute}}=\frac{3.1\times 10^{9} beats}{73 beat/min}$

1 year =525600 mins

Life span = $0.0424\times 10^{9} min=80.66 years$

The person lived for 80.66 years.

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Using the Brønsted-Lowry concept of acids and bases, identify the Brønsted-Lowry acid and base in each of the following reaction

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Answer:

1. HSO³⁻(aq) + H₂O(l) → H₂SO₃(aq) + OH⁻(aq)

The Brønsted-Lowry acid is H₂O and the Brønsted-Lowry base is HSO³⁻

2. (CH₃)₃N(g) + BCl₃(g) → (CH₃)₃NBCl₃(s)

There are no Brønsted-Lowry acids and bases in this reaction.

Explanation:

According to the Brønsted-Lowry concept, when an acid (HA) and a base (B) undergoes a chemical reaction, the acid (HA) loses a proton and forms its conjugate base (A⁻), whereas the base gains (B) the proton to form its conjugate acid (HB⁺).

The chemical equation for this reaction is:

HA + B ⇌ A⁻ + HB⁺

Given reactions:

1. HSO³⁻(aq) + H₂O(l) → H₂SO₃(aq) + OH⁻(aq)

The Brønsted-Lowry acid is H₂O and the Brønsted-Lowry base is HSO³⁻

Reason: In this reaction, the acid H₂O loses a proton and forms its conjugate base, OH⁻. Whereas, the base HSO³⁻ gains a proton to form its conjugate acid, H₂SO₃.

2. (CH₃)₃N(g) + BCl₃(g) → (CH₃)₃NBCl₃(s)

There are no Brønsted-Lowry acids and bases in this reaction.

Reason: In this reaction, there is no exchange of proton between the acid and the base.

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Answer:

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an electron is at higher energy when excited and at lower energy when at ground state.

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