Answer is: <span>one chlorine atom.
They form ionic compound potassium-chloride (KCl).
</span>Electron configuration of potassium: ₁₉K 1s²2s²2p⁶3s²3p⁶4s¹.
Electron configuration of chlorine: ₁₇Cl 1s²2s²2p⁶3s²3p⁵.
Potassium lose one electron to <span>attains a stable electron configuration of noble gas argon (Ar).</span>
Answer: First separate the iron filings using a magnet, and then filter the sand out of the water.
Explanation: hope it helps
Answer:
SeCl₆ < SeF₂ < SeO₂
Explanation:
To determine the order of the bond angle of the compound, we need to determine the hybridization of each compound given.
For:
SeO₂, The hybridization is sp² because the Se is doubly bonded to O at both sides and Se contains a lone pair of electrons.
SeCl₆, Se is attached to six different Cl atoms via a single bond in a hexagonal shape. Thus, SeCl₆ hybridization is sp³d²
SeF₂, Here, Se is singly bonded to F atoms on both sides and Se contains a lone pair of electrons. The hybridization is sp³
Therefore, the bond angle in sp² = 120°, sp³ = 109.8°, sp³d² = 90°
Hence, the order is: SeCl₆ < SeF₂ < SeO₂
Answer:
C.
Water has a greater density than alcohol.
Explanation:
From the experiment, it can be shown that water has a greater density than the alcohol.
The ice cube is able to float in the water because, the density of the ice is less than the density of the water.
Density of ice < Density of water
So, the ice cube sinks in alcohol because the density of the ice cube is greater than the density of the alcohol.
Density of ice > Density of alcohol
Therefore, we can assume that since the density of ice is greater than density of alcohol, then the density of water is greater than that of the alcohol.
Because it has high electrical conductivity
