Answer:
the correct answer is C 1/32 Ib
Step-by-step explanation:
Can you give me brainlest
<h3>
Answer: 4</h3>
===========================================
Explanation:
For now, ignore the variables. Let's just focus on the coefficients 12 and 16.
The GCF of 12 and 16 is 4 because this is the largest factor they have in common.
12 = 4*3
16 = 4*4
You could create a factor tree to get the prime factorization of each number
12 = 2*2*3
16 = 2*2*2*2
Each factor tree has two copies of '2' leading to the GCF 2*2 = 4.
--------
Now let's go back to the variables. The term 12n and 16w^3 do not have any variables in common. So the final answer won't have any variables in it. If both terms had say a 'w' in them, then w would somehow be involved in the GCF. But that's not the case here. So we just stick to 4 as our answer.
--------
Side note: If you had 12n+16w^3 and you wanted to factor, then you would factor out the GCF 4 to get 12n+16w^3 = 4(3n+4w^3). Use the distribution rule to confirm this.
Where is the rest? What are the following figures?
<u>Answer:</u>
<u>Answer:a. Since 20° is in the first quadrant, the reference angle is 20° .</u>
<u>Answer:a. Since 20° is in the first quadrant, the reference angle is 20° .b. Reference Angle: the acute angle between the terminal arm/terminal side and the x-axis. The reference angle is always positive. In other words, the reference angle is an angle being sandwiched by the terminal side and the x-axis. It must be less than 90 degree, and always positive.</u>
<u>Answer:a. Since 20° is in the first quadrant, the reference angle is 20° .b. Reference Angle: the acute angle between the terminal arm/terminal side and the x-axis. The reference angle is always positive. In other words, the reference angle is an angle being sandwiched by the terminal side and the x-axis. It must be less than 90 degree, and always positive.c. The rays corresponding to supplementary angles intersect the unit circles in points having the same y-coordinate, so the two angles have the same sine (and opposite cosines).</u>
<em>h</em><em>o</em><em>p</em><em>e</em><em>f</em><em>u</em><em>l</em><em>l</em><em>y</em><em>,</em>
<em>Z</em><em>a</em><em>r</em><em>a</em><em>♡</em>
Answer:
Step-by-step explanation:
we know that
The area of the resulting two-dimensional cross-section is the area of a rectangle
The area of a rectangle is equal to
we have
substitute