Answer:
C
Step-by-step explanation:
Since the triangle is right with hypotenuse QR
Use Pythagoras' identity to solve for QR
The square on the hypotenuse is equal to the sum of the squares on the other two sides, that is
QR² = 8² + (8
)²
= 64 + 192
= 256 ( take the square root of both sides )
QR = 
= 16
Answer:
x = -33
Step-by-step explanation:
2/3(x+6)=-18
Multiply each side by 3/2
3/2*2/3(x+6)=-18*3/2
x+6 = -27
Subtract 6 from each side
x +6-6 = -27-6
x = -33
First one:
you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so
when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)
-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m
add
-10m-13m+2m^4-20m^4
-23m-18m^4
second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms
(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8
Here's the solution ~
Therefore, the correct choice is A
The order of rotational symmetry of a kite is 1
