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2 years ago

Graph the equations to find the solution(s) to the system.

Mathematics

1 answer:

liraira [26]2 years ago

6 0

By graphing both equations, we see that the solutions of the system of equations are (1.05, 4.05) and (-4.97, - 1.97)

<h3>How to solve the system of equations?</h3>

Here we have the system of equations:

y = x + 3

y = 13*(x + 5)*(x - 1).

To solve this system graphically, we need to graph both equations and see where the curves intercept.

The graph of the two equations can be seen below.

There are two solutions, one is (1.05, 4.05) and the other is (-4.97, - 1.97)

If you want to learn more about systems of equations:

brainly.com/question/13729904

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Which of the following is an arithmetic sequence?

laiz [17]

Answer:

0,2,4,6

Step-by-step explanation:

This sequence is arithmetic because the same number is being added each time: 2. With the others, the number being added changes every time.

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3 years ago

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Anon25 [30]

Answer:

A) 40

B) 20

Step-by-step explanation:

By <em>Length · Width · Height</em>

A) (5) · (4) · (2) = 40

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B) (5) · (4) · (1) = 20

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2 years ago

A runner runs 8 miles in 92 minutes. What is the runner's unit rate.

scoundrel [369]

11.5 minutes per mile

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3 years ago

The solution set of 4x-(x+7)=2(x+3)

maria [59]

Step-by-step explanation:

<h3><u>To</u><u> </u><u>Solve</u><u>:</u><u>-</u></h3>

$\\ \tt{:}\leadsto 4x-(x+7)=2(x+3)$

<h3><u>SOL</u><u>UTION</u><u>:</u><u>-</u></h3>

$\\ \tt{:}\leadsto 4x-(x+7)=2(x+3)$

$\\ \tt{:}\leadsto 4x-x-7=2x+6$

$\\ \tt{:}\leadsto 3x-7=2x+6$

$\\ \tt{:}\leadsto 3x-2x=6+7$

$\\ \tt{:}\leadsto x=13$

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2 years ago

(a) How many integers in the range 1 through 120 are integer multiples of 2, 3, or 5? keyboard_arrow_down Solution (b) How many

Umnica [9.8K]

Answer:

(a) 88 integers

(b) 92 integers

Step-by-step explanation:

(a) integers whose last digits are divisible by 2 are multiples of two or numbers whose digits ends with zero. So for number 1-120 , all the even numbers which are sixty in number are are multiples of two.

For 3, numbers whose digits sum is divisible by three are multiples of three. 3,6,9,12,15,18,21,24,27,30 are multiples of three from numbers 1-30. we have four 30s in 120. which means numbers of integers will be 10*4 = 40integers. However out of these numbers , half are also integers of 2 which reduces the number added to 20integers.

For 5, numbers whose digits ends with 5 or 0 are multiples of 5. this gives us 24 integers for 1-120. but out of these 24integers, 16 are common integers of 2 and 3 which reduces the number added to 8integers.

Thus from 1-120 the intergers of 2,3 or 5 = 60+20+8 = 88integers.

(b) if we are considering from numbers 1-140;

for 2 we wil have 70 integers,

for 5 we will have 28 integers, but those integers that end with 0 are also integers of 2 which reduces the number added to 14.

For 7, numbers 7,14,21,28,35,42,49,56,63,70 are multiples of three from 1-70. This pattern is repeated from number 71-140. hence we have 20 integers in all. However 12 of the multiples are also multiples of either 2 or 5 which reduces the number to 8 integers.

Thus from 1-140, the integers of 2, 5, or 7 = 70+14+8 = 92integers

3 0

3 years ago