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2 years ago

400

Mathematics

1 answer:

ser-zykov [4K]2 years ago

3 0

It exists not linear the curve indicates that the rate of change exists not constant.

<h3>What is a linear Function?</h3>

Linear functions exist as those whose graph exists as a straight line. A linear function exists that can be characterized by the equation

y = mx + c, Where m exists the slope and c exists the intercept on the

y-axis. A linear function contains one independent variable and one dependent variable.

Therefore, the correct answer is option c) No, because the curve indicates that the rate of change is not constant.

To learn more about Linear Function refer to:

brainly.com/question/21107621

#SPJ9

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I need help quickly and fast

Andrej [43]

i might be wrong about this one

5 0

3 years ago

Read 2 more answers

The LCD of theses fractions? y/x + y/3+ y+1/y Answers: 3x+y x+3+y 3x+y

Dahasolnce [82]

3xy

y(3y)/3xy + y(xy)/3xy + (y+1)(3x)/3xy 

NOW since all of the fractions have a denominator of 3xy, drop the denominators and solve using the numerators. 

y(3y) + y(xy) + (y+1)(3x) 

3y^2 + xy^2 + 3xy +3x 

cannot simplify further.

5 0

3 years ago

Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(−2, 1) and Q(8, 9)

IrinaK [193]

Answer:

Equation of the circle (x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

Step-by-step explanation:

Step(i):-

Given endpoints of diameter P(−2, 1) and Q(8, 9)

Centre of circle = midpoint of diameter

Centre = $(\frac{-2+8}{2} ,\frac{1+9}{2} )$

Centre (h, k) = (3 , 5)

Step(ii):-

The distance of two end points

PQ = $\sqrt{(x_{2}-x_{1} )^{2} +(y_{2} -y_{1} )^{2} }$

$PQ= \sqrt{(8+2 )^{2} +(8 )^{2} }$

PQ = √164 = 12.8

Diameter d = 2r

radius r = d/2

Radius r = 6.4

Final answer:-

Equation of the circle

(x-h)²+(y-k)² = r²

(x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

x² -6x +y² -10y = 40.96-34

x² -6x +y² -10y -7= 0

4 0

3 years ago

For the straight line defined by the points (4,57) and (6,91) , determine the slope ( m ) and y-intercept ( ???? ). Do not round

Ksivusya [100]

$\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{57})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{91}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{91}-\stackrel{y1}{57}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{4}}}\implies \cfrac{34}{2}\implies 17 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{57}=\stackrel{m}{17}(x-\stackrel{x_1}{4})\implies y-57=17x-68$

$\bf y=17x-11\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad \begin{cases} \stackrel{slope}{17}\\\\ \stackrel{y-intercept}{(0,-11)} \end{cases}$

4 0

3 years ago

Last year, Maria had $10,000 to invest. She invested some of it in an account that paid 6% simple interest per year, and she inv

denis-greek [22]

Answer:

$3,000 invested at 6%

$7,000 invested at 10%

Step-by-step explanation:

Maria had total $10,000 to invest.

Let x be the amount that Maria invested initially at 6% interest rate.

0.06x

Then she invested the remaining amount at 10% interest rate.

0.10(10,000 - x)

She received a total of $880 in interest.

0.06x + 0.10(10,000 - x) = 880

0.06x + 1000 - 0.10x = 880

-0.04x = 880 - 1000

-0.04x = -120

0.04x = 120

x = 120/0.04

x = $3,000

This is the amount that Maria invested initially at 6% interest rate.

The remaining amount is

10,000 - 3,000

$7,000

This is the remaining amount that she invested at 10% interest rate.

3 0

3 years ago