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2 years ago

Kyle is renting a jet ski for the day. Below are his two options.

Mathematics

1 answer:

Ira Lisetskai [31]2 years ago

3 0

Hi Lawrence!

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We Know:

Powersports Plus: $30 an hour plus a non-refundable deposit of $50.

Sun & Surf: $20 an hour plus a non-refundable deposit of $80.

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Equation:

x = per hour

y = total

Powersports: 30x + 50 = y

Sun and Surf: 20x + 80 = y

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Solution: (Add the deposit then start adding hourly costs)

Powersports: 80, 110, 140

Sun and Surf: 100, 120, 140

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Answer: After 3 hours both companies will cost the same amount of money.

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Hope This Helps :)

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(x^2y+e^x)dx-x^2dy=0

klio [65]

It looks like the differential equation is

$\left(x^2y + e^x\right) \,\mathrm dx - x^2\,\mathrm dy = 0$

Check for exactness:

$\dfrac{\partial\left(x^2y+e^x\right)}{\partial y} = x^2 \\\\ \dfrac{\partial\left(-x^2\right)}{\partial x} = -2x$

As is, the DE is not exact, so let's try to find an integrating factor µ(x, y) such that

$\mu\left(x^2y + e^x\right) \,\mathrm dx - \mu x^2\,\mathrm dy = 0$

*is* exact. If this modified DE is exact, then

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \dfrac{\partial\left(-\mu x^2\right)}{\partial x}$

We have

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu \\\\ \dfrac{\partial\left(-\mu x^2\right)}{\partial x} = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu \\\\ \implies \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu$

Notice that if we let µ(x, y) = µ(x) be independent of y, then ∂µ/∂y = 0 and we can solve for µ :

$x^2\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} - 2x\mu \\\\ (x^2+2x)\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} \\\\ \dfrac{\mathrm d\mu}{\mu} = -\dfrac{x^2+2x}{x^2}\,\mathrm dx \\\\ \dfrac{\mathrm d\mu}{\mu} = \left(-1-\dfrac2x\right)\,\mathrm dx \\\\ \implies \ln|\mu| = -x - 2\ln|x| \\\\ \implies \mu = e^{-x-2\ln|x|} = \dfrac{e^{-x}}{x^2}$

The modified DE,

$\left(e^{-x}y + \dfrac1{x^2}\right) \,\mathrm dx - e^{-x}\,\mathrm dy = 0$

is now exact:

$\dfrac{\partial\left(e^{-x}y+\frac1{x^2}\right)}{\partial y} = e^{-x} \\\\ \dfrac{\partial\left(-e^{-x}\right)}{\partial x} = e^{-x}$

So we look for a solution of the form F(x, y) = C. This solution is such that

$\dfrac{\partial F}{\partial x} = e^{-x}y + \dfrac1{x^2} \\\\ \dfrac{\partial F}{\partial y} = e^{-x}$

Integrate both sides of the first condition with respect to x :

$F(x,y) = -e^{-x}y - \dfrac1x + g(y)$

Differentiate both sides of this with respect to y :

$\dfrac{\partial F}{\partial y} = -e^{-x}+\dfrac{\mathrm dg}{\mathrm dy} = e^{-x} \\\\ \implies \dfrac{\mathrm dg}{\mathrm dy} = 0 \implies g(y) = C$

Then the general solution to the DE is

$F(x,y) = \boxed{-e^{-x}y-\dfrac1x = C}$

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3 years ago

I need help with this please

alexdok [17]

Answer:

polygons

Step-by-step explanation:

this is a hexagon so the sum of interior angles is 720. so add all of those angles and expressions and set it equal to 720. collect like terms and solve for x

once you have x, evaluate and get the exact angle measurements.

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Mama L [17]

Answer:

MEE PLAESE

Step-by-step explanation:

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3 years ago

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The marijority of the population in the United states _________.

Nadusha1986 [10]

It should be C english :)

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2 years ago

Find the area of the

Alex73 [517]

162 m^2

you can make a triangle in the corner with legs length s/2 and the angles are 45 degrees. in a 45 45 90 triangle, the legs are h/sqrt(2) where h is the hypotenuse. this means that s/2=9/2 sqrt(2), s=9 sqrt(2)

and s^2=162

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2 years ago