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irina [24]
3 years ago
15

Factoring as a product of two binomials x2+10x+24

Mathematics
2 answers:
GarryVolchara [31]3 years ago
8 0

Answer:

(x + 6)(x + 4)

Step-by-step explanation:

Given

x² + 10x + 24

Consider the factors of the constant term (+ 24) which sum to give the coefficient of the x- term (+ 10)

The factors are 6 and 4, since

6 × 4 = 24 and 6 + 4 = 10, thus

x² + 10x + 24 = (x + 6)(x + 4)

MrMuchimi3 years ago
5 0

That can be factored to:

(x+6)(x+4)

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A bottle contains 5/9 liters of soda. Keisha has 3 of these bottles.
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Answer: 1 2/3 Liters

Step-by-step explanation:

  • Create the equation

The equation is going to be the amount of soda, multiplied by the amount of bottles Keisha has

5/9 x 3/1 (3/1 is equivalent to having 3 or 1+1+1)

  • Solve

We are going to multiple the numbers, numerator by numerator, and denominator by denominator since we do not need to add or subtract

  1. Numerator= 5x3=15
  2. Denominator= 9x1=9

Your improper awnser would be 15/9

DO NOT STOP HERE THIS IS NOT THE SIMPLEST FORM

  • Create the simplest mixed number

15/9 is equal to 15 divided by 9

we can fit 1 9 in 15 without going over

1 ?/15

15-9=6

1 6/9

  • Simplify

6 and 9 are both divisible by 3

6 divided by 3 = 2

9  divided by 3 = 3

1 6/9=1 2/3

  • Awnser and add your units

1 2/3 is the simpelest form, this can not be further divided.

1 2/3 Liters of Soda

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find an nth-degree polynomial function with real coefficients satisfying the given conditions. If you are using a graphing utili
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( – 1, – 5) 7x+2y=13, 4x+4y=14
serious [3.7K]

Answer:

{x,y} = {6/5,23/10}

Step-by-step explanation:

 [1]    7x + 2y = 13

  [2]    4x + 4y = 14  <---------- linear equations given

Graphic Representation of the Equations : PICTURE
2y + 7x = 13        4y + 4x = 14  

Solve by Substitution :

// Solve equation [2] for the variable  y

[2]    4y = -4x + 14

[2]    y = -x + 7/2

// Plug this in for variable  y  in equation [1]

  [1]    7x + 2•(-x +7/2) = 13

  [1]    5x = 6

// Solve equation [1] for the variable  x

  [1]    5x = 6

  [1]    x = 6/5

// By now we know this much :

   x = 6/5

   y = -x+7/2

// Use the  x  value to solve for  y

   y = -(6/5)+7/2 = 23/10

// Plug this in for variable  y  in equation [1]

 [1]    7x + 2•(-x +7/2) = 13

  [1]    5x = 6

// Solve equation [1] for the variable  x

 [1]    5x = 6

[1]    x = 6/5

// By now we know this much :

   x = 6/5

   y = -x+7/2

// Use the  x  value to solve for  y

  y = -(6/5)+7/2 = 23/10

4 0
2 years ago
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