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2 years ago

Factoring as a product of two binomials x2+10x+24

Mathematics

2 answers:

GarryVolchara [31]2 years ago

8 0

Answer:

(x + 6)(x + 4)

Step-by-step explanation:

Given

x² + 10x + 24

Consider the factors of the constant term (+ 24) which sum to give the coefficient of the x- term (+ 10)

The factors are 6 and 4, since

6 × 4 = 24 and 6 + 4 = 10, thus

x² + 10x + 24 = (x + 6)(x + 4)

MrMuchimi2 years ago

5 0

That can be factored to:

(x+6)(x+4)

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By how much does the dependent variable change in response to a change of 1 unit of the independent variable?

dalvyx [7]

Answer: C) 5

--------------

x = independent variable, y = dependent variable

Assuming this is a linear function, each increase of x by 2 leads to y going up by 10. So 10/2 = 5 is the unit increase each time x bumps up by 1.

-------------------

An alternative is to use the slope formula to get

m = (y2 - y1)/(x2 - x1)

m = (25 - 15)/(4 - 2)

m = 10/2 <--- this expression shows up again

m = 5 <---- leading to the same answer as before

So we see that the slope formula is a more drawn out method to finding the answer.

6 0

2 years ago

Read 2 more answers

A chef uses 8 1/2 cups flour for his gig nine 3/4 cup flour for his pies and 25 2/3 cups flour for his bread will he have any fl

katen-ka-za [31]

Answer:

50-25 2/3 - 9 3/4 - 8 1/2 = 6 1/12

Step-by-step explanation:

To do this without a calculator you need to get common denominator

a good choice would be 12 for the common denominator

50 x 12 = 600

25 x 12 = 300

convert to 2/3 to x/12, multiply top and bottom by 4

2/3 x 4 = 8/12

add this to the 300 to get 308/12

same with the other terms

9 x 12 = 108

convert 3/4 to x/12, multiply top and bottom by 3

3/4 x 3 = 9/12

add this to the 108 to get 117/12

and do the same for the 8 1/2

8x 12 = 96

convert 1/2 to x/12, multiply top and bottom by 6

1/2 = 6/12, add this to the 96

do the subtraction and simplify

8 0

2 years ago

In a company, 80% of the workers are women. If 480 men work for the company, how many workers are there in all? Use pencil

nekit [7.7K]

Answer:

The total workers are 2400.

Step-by-step explanation:

Given:

In company 80% of the workers are women.

480 workers are men.

Now, to find the total workers in all.

In first way:

If women are 80%, then men would be 100-80 = 20%.

Let the total workers be $x$ .

According to question:

$20\%\ of \ x=480$

⇒ $\frac{20}{100} \times x=480$

⇒ $0.20\times x=480$

⇒ $0.20x=480$

Dividing both sides by 0.20 we get:

⇒ $x=2400$ .

Total workers = 2400.

Now, in second way.

Again, let the total workers be $x$ .

According to question:

$x-80\%\ of\ x=480$

⇒ $x-\frac{80}{100}\times x=480$

On solving:

⇒ $x-0.80x=480$

⇒ $0.20x=480$

Dividing both sides by 0.20 we get:

⇒ $x=2400$ .

Total workers = 2400.

Therefore, the total workers are 2400.

7 0

2 years ago

How many solutions does this nonlinear system of equations have?

bulgar [2K]

Answer:

Infinate Solutions.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Consider the differential equation x2y′′ − 9xy′ + 24y = 0; x4, x6, (0, [infinity]). Verify that the given functions form a funda

pantera1 [17]

Answer:

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

$y= c_1x^4+c_2x^6$

Step-by-step explanation:

Given equation is

$x^2y'' - 9xy+24y=0$

This Euler Cauchy type differential equation.

So, we can let

$y=x^m$

Differentiate with respect to x

$y'= mx^{m-1}$

Again differentiate with respect to x

$y''= m(m-1)x^{m-2}$

Putting the value of y, y' and y'' in the differential equation

$x^2m(m-1) x^{m-2} - 9 x m x^{m-1}+24x^m=0$

$\Rightarrow m(m-1)x^m-9mx^m+24x^m=0$

$\Rightarrow m^2-m-9m+24=0$

⇒m²-10m +24=0

⇒m²-6m -4m+24=0

⇒m(m-6)-4(m-6)=0

⇒(m-6)(m-4)=0

⇒m = 6,4

Therefore the auxiliary equation has two distinct and unequal root.

The general solution of this equation is

$y_1(x)=x^4$

and

$y_2(x)=x^6$

First we compute the Wronskian

$W(x)= \left|\begin{array}{cc}y_1(x)&y_2(x)\\y'_1(x)&y'_2(x)\end{array}\right|$

$= \left|\begin{array}{cc}x^4&x^6\\4x^3&6x^5\end{array}\right|$

=x⁴×6x⁵- x⁶×4x³

=6x⁹-4x⁹

=2x⁹

≠0

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

$y= c_1x^4+c_2x^6$

5 0

2 years ago