Answer:
Sum angle of triangle BHD = 180°
36 + 39 + BHD = 180
BHD = 180 - 36 - 39
= 105°
BHD + x° = 180° (straight angle)
105° + x° = 180°
x = 180 - 105
= 75°
csc(2x) = csc(x)/(2cos(x))
1/(sin(2x)) = csc(x)/(2cos(x))
1/(2*sin(x)*cos(x)) = csc(x)/(2cos(x))
(1/sin(x))*1/(2*cos(x)) = csc(x)/(2cos(x))
csc(x)*1/(2*cos(x)) = csc(x)/(2cos(x))
csc(x)/(2*cos(x)) = csc(x)/(2cos(x))
The identity is confirmed. Notice how I only altered the left hand side (LHS) keeping the right hand side (RHS) the same each time.
If you plug in the second equation (x=5-3/2y) into the first, you get:
5(5-3/2y) - 4y = 7
Simplify:
25 - 15/2y - 4y = 7
-15/2 y - 8/2 y = 7-25
23/2 y = 18
y = 18 * 2/23 = 36/23
answer B!
Answer:
I can't see the picture
Step-by-step explanation:
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Is this more then one question?