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mojhsa [17]
3 years ago
13

The perimeter of the patio is 32m. the garden itself is a square shape. what is the total area of the garden and the patio?

Mathematics
2 answers:
Ivahew [28]3 years ago
8 0

Answer:

Step-by-step explanation:

The perimeter of the patio is 32m

Lets say the side length including the garden and patio is x m

so its perimeter in terms of x is 4x

we get the equation 4x=32

hence x=32/4

x=8 m

Means the sides are of 8 m

Now

Area is given by

A=x^2

so

A =8^2

Area =64 sq meter

melamori03 [73]3 years ago
4 0
64 32 divided by 4 is 8 8 tmes 8 is 64

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Lubov Fominskaja [6]
It’s a 90 degree angle. So the equation so be 28+2x =90 and find x from there.


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Answer: 66 miles per hour i belive

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3 years ago
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How do you reduce 2 1/32
loris [4]

Answer:

2\frac{1}{32}=\frac{2\cdot 32+1}{32}=\frac{65}{32}

Step-by-step explanation:

Considering the expression

2\frac{1}{32}

As

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fraction:}\:a\frac{b}{c}=\frac{a\cdot \:c+b}{c}

<em>Improper fraction is a fraction which has numerator greater than denominator, such as 5/3.</em>

So,

2\frac{1}{32}=\frac{2\cdot 32+1}{32}=\frac{65}{32}

As 2\frac{1}{32} is converted into improper fraction  \frac{65}{32} .

And  \frac{65}{32} can not be further reduced.

Therefore,

2\frac{1}{32}=\frac{2\cdot 32+1}{32}=\frac{65}{32}

Keywords: fraction, reduced form, improper fraction

Learn more about fractions from brainly.com/question/535608

#learnwithBrainly

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3 years ago
5 Exam-style ABCD is a kite.
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let's recall that in a Kite the diagonals meet each other at 90° angles, Check the picture below, so we're looking for the equation of a line that's perpendicular to BD and that passes through (-1 , 3).

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of BD

y = \stackrel{\stackrel{m}{\downarrow }}{3}x-1\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line whose slope is -1/3 and passes through point A

(\stackrel{x_1}{-1}~,~\stackrel{y_1}{3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{-\cfrac{1}{3}}[x-\stackrel{x_1}{(-1)}]\implies y-3=-\cfrac{1}{3}(x+1) \\\\\\ y-3=-\cfrac{1}{3}x-\cfrac{1}{3}\implies y=-\cfrac{1}{3}x-\cfrac{1}{3}+3\implies y=-\cfrac{1}{3}x+\cfrac{8}{3}

5 0
3 years ago
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