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artcher [175]
3 years ago
10

If LM bisects Angle JLK find LJ

Mathematics
1 answer:
leonid [27]3 years ago
8 0

Answer:

14 units

Step-by-step explanation:

Given: LM bisects \angle JLK

To find: LJ

Solution:

According to angle bisector theorem,

an angle bisector of a triangle divides the interior angle's opposite side into two segments that are proportional to the other two sides of the triangle.

In \Delta JKL, LM bisects \angle JLK

Using angle bisector theorem,

\frac{LK}{LJ}=\frac{KM}{JM}\\\frac{LK}{LJ}=\frac{KM}{JK-MK}\\\frac{8}{x+3}=\frac{4}{x-4}\\8(x-4)=4(x+3)\\8x-32=4x+12\\8x-4x=12+32\\4x=44\\x=\frac{44}{4}=11

So,

LJ=x+3=11+3=14\,\,units

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Answer:

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Step-by-step explanation:

Given

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Using the midpoint formula

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\left(-7,\:-2.5\right)=\left(\frac{x_2+\left(-9\right)}{2},\:\:\frac{y_2+\left(-4\right)}{2}\right)

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x₂ - 9 + 9 = -14 + 9

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y₂ - 4 = -5

adding 4 to both sides

y₂ - 4 + 4 = -5 + 4

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Therefore, the coordinates of the point b are:

b(x₂, y₂)  = (-5, -1)

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Hello there!

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