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artcher [175]
3 years ago
10

If LM bisects Angle JLK find LJ

Mathematics
1 answer:
leonid [27]3 years ago
8 0

Answer:

14 units

Step-by-step explanation:

Given: LM bisects \angle JLK

To find: LJ

Solution:

According to angle bisector theorem,

an angle bisector of a triangle divides the interior angle's opposite side into two segments that are proportional to the other two sides of the triangle.

In \Delta JKL, LM bisects \angle JLK

Using angle bisector theorem,

\frac{LK}{LJ}=\frac{KM}{JM}\\\frac{LK}{LJ}=\frac{KM}{JK-MK}\\\frac{8}{x+3}=\frac{4}{x-4}\\8(x-4)=4(x+3)\\8x-32=4x+12\\8x-4x=12+32\\4x=44\\x=\frac{44}{4}=11

So,

LJ=x+3=11+3=14\,\,units

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I need help finding x please?
enot [183]

\large\mathfrak{{\pmb{\underline{\blue{To\:find}}{\blue{:}}}}}

The value of x.

\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}

\longrightarrow{\green{x\:=\: 25° }} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

We know that,

\sf\purple{Sum\:of\:angles\:on\:a\:straight\:line\:=\:180°}

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\large\mathfrak{{\pmb{\underline{\pink{To\:verify}}{\pink{:}}}}}

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\boxed{Hence\:verified.}

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